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What are the next three numbers in the pseudo-random number generator 3x 2mod 11 starting from 5?
Wiki User
∙ 8y ago
I guess the formula is 3x² MOD 11 where x is the last pseudo-random number. Just plug in the values:
x = 5 → next_val = 3 × 5² MOD 11 = 9
x = 9 → next_val = 3 × 9² MOD 11 = 1
x = 1 → next_val = 3 ×1² MOD 11 = 3
So the next three values would be 9, 1, 3.
Wiki User
∙ 8y ago
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