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I guess the formula is 3x² MOD 11 where x is the last pseudo-random number. Just plug in the values:

x = 5 → next_val = 3 × 5² MOD 11 = 9

x = 9 → next_val = 3 × 9² MOD 11 = 1

x = 1 → next_val = 3 ×1² MOD 11 = 3

So the next three values would be 9, 1, 3.

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