One possible position to value rule is Un = (20n3 - 90n2 + 160n - 75)/3 Accordingly, the next three numbers are U4 = 325 U5 = 655 U6 = 1165 Alternatively, give my any three numbers that you want as the next three and I will find you a polynomial of order 6 that will fit the 4 given number and the 3 that you specify.
1, 2, 67, 134.
√121 < √134 < √144√121 = 11√144 = 1211 < √134 < 12Answer: √134 is between 11 and 12. More
134 and 0 133 and 1 132 and 2 131 and 3 see the pattern?
2 , 67 & 134.
The average is the sum of the numbers in the set divided by the number of numbers in the set. In this case it is (125+143+134)/3=134.
One possible position to value rule is Un = (20n3 - 90n2 + 160n - 75)/3 Accordingly, the next three numbers are U4 = 325 U5 = 655 U6 = 1165 Alternatively, give my any three numbers that you want as the next three and I will find you a polynomial of order 6 that will fit the 4 given number and the 3 that you specify.
The numbers are -134, -132 and -130.
1, 2, 67, 134.
402. The sequence alternates between multiply by 3, and add 11.
There are three significant figures in the number 134.
√121 < √134 < √144√121 = 11√144 = 1211 < √134 < 12Answer: √134 is between 11 and 12. More
134.
1 x 134, 2 x 67
These numbers: 1, 2, 4, 67, 134, 268.
Divide the sum of the three consecutive odd integers by 3: 402/3 = 134. The smallest of these integers will be two less than 134 and the largest will be two more than 134, so the three consecutive odd integers will be 132, 134, and 136.
134 and 0 133 and 1 132 and 2 131 and 3 see the pattern?