-7 -11 -15
You subtract 4 each time
1 squared, 2 squared, 3 squared etc so the next 3 terms are 36,49 and 64.
The sequence given is based on the cubes of consecutive integers: (1^3 = 1), (2^3 = 8), and (3^3 = 27). The next two terms would be (4^3 = 64) and (5^3 = 125). Therefore, the next two terms are 64 and 125.
Divide by three. 4, 4/3, 4/9
13 21 34 55
10, 48 and 116. These are derived using the cubic generator: Un = (-4n3 + 27n2 - 47n + 30)/3 for n = 1, 2, 3, ...
1 squared, 2 squared, 3 squared etc so the next 3 terms are 36,49 and 64.
1, -3, -7
-1 -3
The sequence given is based on the cubes of consecutive integers: (1^3 = 1), (2^3 = 8), and (3^3 = 27). The next two terms would be (4^3 = 64) and (5^3 = 125). Therefore, the next two terms are 64 and 125.
Each number is three times the previous number.
Divide by three. 4, 4/3, 4/9
2.6 and 3.
You are dividing by 3 each time, so the next 3 numbers are 8, 8 over 3 and 8 over 9.
Divide by three. 4, 4/3, 4/9
9 The three factors are 1, 3, and 9. 9 The three factors are 1, 3, and 9.
1 = * 2 = ? 3 = *?
Which sequence? Oh, that one! The first three terms are 1, 2 and 72.