If order doesn't matter, 15 combinations and if order does matter, 360 combinations are possible.
You have 6 choices of cards, two possibilities with the coin and 6 numbers on the cube. The number of combinations is : 6 x 2 x 6 = 72.
There are 18*17*16/6 = 816 of them!
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
If the order of the numbers are important, then this is a simple combination problem. There are 10 possible numbers to choose from for the first number. Then there are 9 options for the second number. Then there are 8 options for the third, and so on. Thus, the number of possible combinations can be calculated as 10x9x8x7x6x5. This comes out at 151,200 possible combinations.
To calculate the number of possible combinations from 10 items, you can use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, n is the total number of items (10) and r is the number of items you are choosing in each combination (which can range from 1 to 10). So, if you are considering all possible combinations (r=1 to 10), the total number of combinations would be 2^10, which is 1024.
If order doesn't matter, 15 combinations and if order does matter, 360 combinations are possible.
61
6 different combinations can be made with 3 items
You have 6 choices of cards, two possibilities with the coin and 6 numbers on the cube. The number of combinations is : 6 x 2 x 6 = 72.
There are 18*17*16/6 = 816 of them!
The number of combinations of 6 letters is 6! or 720.
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
If the order of the numbers are important, then this is a simple combination problem. There are 10 possible numbers to choose from for the first number. Then there are 9 options for the second number. Then there are 8 options for the third, and so on. Thus, the number of possible combinations can be calculated as 10x9x8x7x6x5. This comes out at 151,200 possible combinations.
In a 7 segment display, the symbols can be created using a selected number of segments where each segment is treated as a different element.When 1 segment is used, the possible positions are 7because it can be any of the 7 segments (7C1=7).When 2 segments are used, the number of possible combinations are 7C2=21.When 3 segments are used, the number of possible combinations are 7C3=35When 4 segments are used, the number of possible combinations are 7C4=35When 5 segments are used, the number of possible combinations are 7C5=21When 6 segments are used, the number of possible combinations are 7C6=7When 7 segments are used, the number of possible combinations are 7C7=1Adding the combinations, 7+21+35+21+7+1=127Therefore, 127 symbols can be made using a 7 segment display!
That would be the number of possible combinations of men, multiplied by the number of possible combinations of men. For each subset, the total number of possible combinations will be the factorial of the number available, divided by the factorial of that number minus six. In other words:x = 10!/(10 - 6)! * 12!/(12-6)!∴ x = 10!/4! * 12!/6!∴ x = (10 * 9 * 8 * 7 * 6 * 5) * (12 * 11 * 10 * 9 * 8 * 7)∴ x = 151200 * 665280∴ x = 100590336000So there are one hundred billion, five-hundred-and-ninety million, three-hundred-and-thirty-six thousand possible jury combinations from that selection.
252 combinations, :)