There are technically infinitely many solutions.
But multiply 9 by any whole number, and the product will be evenly divisible by 9.
Ex: 9*1 = 9 and 9/9 = 1
9*2 = 18 and 18/9 = 2
9*3 = 27 and 27/9 = 3
...
9*100 = 900 and 900/9 = 100
You get the idea.
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All numbers divisible by 3 are NOT divisible by 9. As an example, 6, which is divisible by 3, is not divisible by 9. However, all numbers divisible by 9 are also divisible by 3 because 9 is divisible by 3.
Yes; all numbers that are divisible by 9 are divisible by 3.
All numbers divisible by 9 are divisible by 3; since 9 = 3 x 3 all multiples of 9 are also multiples of 3. However, all numbers divisible by 3 are not divisible by 9, eg 6 = 2 x 3 but 6 is not divisible by 9 (since 6 is not a multiple of 9) - it only takes one counter example to disprove a theory.
ANSWER:The numbers that are divisible by 9 are the numbers whose sum of the digits is a multiple of 9Example:27 = 2 + 7 = 9 (9 is a multiple of 9 thus 27 is divisible by 9)99 = 9 + 9 = 18 (18 is a multiple of 9 thus 99 is divisible by 9)
no, 18 is divisible by 9 but not by 4.