Possibly none; the answer to the question depends on what was measured, and how.
Since the range of the values and their standard deviation is fairly small, one wouldn't necessarily brand any of these values an outliner in the general case. An outliner is identified by being far away from the dataset's mean.
For example, assume this data set represents the weight of human babies at the same age, in pounds. Maybe the 14 pound baby is strong, much stronger than the 10 bound babies at the lighter end of the range, but its weight is still within a plausible range. A baby weight of 140 pounds, for example, would be a clear outliner - the scale could have been broken, of a comma was forgotten after the first two digits.
There are three modes: 11, 12 and 13
7777777777888888899,999999-,10 10, 10, 10 10,10 10,10 11, 11, 11, 11, 11 11, 11 11, 12 12, 12 12, 12 12, 12 10, 13, 13, 13, 13, 13, 13, 13, 13, 14, 14, 15, 15, 15, 16, 16, 16, 17, 18, 19,20
13 13 # of poker hands with 3 clubs & 2 heards = ( ) ( ) 3 2 = (13!)( 13!) / (10!*3!*11!*2) = (13!)( 13!) / (10!*11!*12) = (13!)( 13!) / (10!*12!) = 13 * 13* 12 * 11 = 22308 #
11
11
There are three modes: 11, 12 and 13
7777777777888888899,999999-,10 10, 10, 10 10,10 10,10 11, 11, 11, 11, 11 11, 11 11, 12 12, 12 12, 12 12, 12 10, 13, 13, 13, 13, 13, 13, 13, 13, 14, 14, 15, 15, 15, 16, 16, 16, 17, 18, 19,20
(4*10+11+2*12+13+2*14)/10 = 11.6
It is (8+6+11+12+13)/5 = 10
he was about 11 or 12
13 13 # of poker hands with 3 clubs & 2 heards = ( ) ( ) 3 2 = (13!)( 13!) / (10!*3!*11!*2) = (13!)( 13!) / (10!*11!*12) = (13!)( 13!) / (10!*12!) = 13 * 13* 12 * 11 = 22308 #
10 7 11 12 9 13 14 11 15 16 13 17 18 15 19 20...
that does not make any sense
7, 10, 11, 12, 13, 14, 17
Mean: 20.2222222 Median: 12 Mode: 11 Range: 79
The answer is 15 because the pattern is subtract one, add two
The least common multiple of the numbers 11, 12 and 13 is 1,716.