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The points are: x = 0 and y = -1/10.

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13y ago

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What is a possible first step in eliminating a variable in the following system of equations 4x plus 5y equals -23 3x plus 10y equals -14?

A possible first step in eliminating a variable in the system of equations (4x + 5y = -23) and (3x + 10y = -14) is to manipulate the equations to align the coefficients of one of the variables. For instance, you can multiply the first equation by 2 to obtain (8x + 10y = -46). This will allow you to eliminate the (y) variable by subtracting the second equation from the modified first equation.


What is 10y plus 40?

10y plus 40 equals 50y.


How do you solve the system of equation problem in algebra 8x-10y equals 2 added with 7x-5y equals 13?

8x - 10y = 27x - 5y = 13First, we need to eliminate one of the variables. For this, we would like to have them with the same coefficient but different sign. We can do this if we multiply by -2 the second equation.8x - 10y = 2-2(7x - 5y) = -2(13)8x - 10y = 2-14x +10y = -26Now, we can add both equations, and solve for x.(8x - 10y) + (-14x + 10y) = (2) + (-26)(8x - 14x) +(-10y + 10y) = (2 - 26)-6x = - 24-6x/-6 = - 24/-6x = 4Substitute 4 for x in the first equation:8x - 10y = 28(4) - 10y = 232 - 10y = 232 - 32 - 10y = 2 - 32-10y = -30-10y/-10 = -30/-10y = 3Thus, the solution of the system is (4, 3).Check:


-2x-10y equals -12 and 3x plus y equals 4?

Treat it as a simultaneous equation question: -2x-10y = -12 3x+y = 4 Multiply all terms in the bottom equation by 10 in order to eliminate y: -2x-10y = -12 30x+10y = 40 Add both equations together: 28x+0 = 28 Divide both sides of the equation by 28 to find the value of x: x = 1 Substitute the value of x into the original equations to find the value of y: x = 1 and y = 1


If 10y equals 5 what is y?

10y = 5 y = 5/10 Therefore, y = 0.5


How do you write 4x equals 10y-8 in standard form?

You're there. 4x = 10y - 8.[so subtract 10y from both sides, 4x - 10y = -8]multiply b.s. by -1 , gives -4x +10y = 8


What is 10y equals 2y-6y plus 7?

10y = 2y - 6y + 7 10y =-4y + 7 10y +4y = 7 14y = 7 y = 1/2 = .5


10y equals 2y plus 4 plus 7y?

10y = 9y + 4, so y = 4


What are the order pairs for 6x - 10y equals 2 and 2x plus 5y equals 9?

x = 2 and y = 1 The lines intersect at the point (2, 1)


Help me solve this equation by substitution. x-5y equals 10 2x-10y equals 20?

what is the solution of x-5y=10 and 2x-10y=20


How do you find the solutions of the simultaneous equations of 2x plus 5y equals 16 and -5x-2y equals 2 showing work in step by step stages?

1 If: 2x+5y = 16 and -5x-2y = 2 2 Then: 2*(2x+5y =16) and 5*(-5x-2y = 2) is equvalent to the above equations 3 Thus: 4x+10y = 32 and -25x-10y = 10 4 Adding both equations: -21x = 42 or x = -2 5 Solutions by substitution: x = -2 and y = 4


What is the slope of the line 20x - 10y equals 32?

2