11 = 6+5 is the only solution, so there are two combinations
first dice : 6, second dice : 5
first dice : 5, second dice : 6
Of the 36 possible combinations rolling two dice there are 2 combinations that add up to 11 so the odds are 18:1
The probability of rolling a 9 with two dice is 4/36 or 1/9. There are 36 possible combinations and a 9 is obtained by rolls of 3,6; 4,5; 6,3; & 5,4.
There are 8 possible combinations that would produce a 5 or 9 and 8/36=2/9.
There is 62 or 36 possible outcomes rolling two dice.
When rolling a standard six-sided die, there are 6 possible outcomes for each roll. If you roll two dice, the total number of combinations is 6 (for the first die) multiplied by 6 (for the second die), resulting in 36 different combinations. For three dice, it would be 6 × 6 × 6, equaling 216 combinations. In general, for n dice, the number of combinations is (6^n).
Of the 36 possible combinations rolling two dice there are 2 combinations that add up to 11 so the odds are 18:1
The probability of rolling a 9 with two dice is 4/36 or 1/9. There are 36 possible combinations and a 9 is obtained by rolls of 3,6; 4,5; 6,3; & 5,4.
The chance is 1/36. (There are 36 possible combinations for two 6-sided dice, but only 18 separate combinations when the dice are not considered seperately.)
Te probability of rolling a sum of 7 with two fair dice is 6 in 36, or 1 in 6, or about 0.1667.Of all the possible combinations of two dice, the sum of 7 has the highest probability, with the other combinations decreasing down to 2 and 12, with probabilities of 1 in 36, or about 0.0278.
There are 8 possible combinations that would produce a 5 or 9 and 8/36=2/9.
There is 62 or 36 possible outcomes rolling two dice.
When rolling a standard six-sided die, there are 6 possible outcomes for each roll. If you roll two dice, the total number of combinations is 6 (for the first die) multiplied by 6 (for the second die), resulting in 36 different combinations. For three dice, it would be 6 × 6 × 6, equaling 216 combinations. In general, for n dice, the number of combinations is (6^n).
The probability of rolling a full house (three of one number and two of another) with 5 dice can be calculated by considering the total combinations of dice rolls. There are 6 possible values for the three-of-a-kind and 5 remaining values for the pair, leading to (6 \times 5 = 30) combinations. The total number of possible outcomes when rolling 5 dice is (6^5 = 7776). Thus, the probability of rolling a full house is approximately ( \frac{30}{7776} ), which simplifies to about 0.00386, or 0.386%.
a lot
15/21= 71.43% chance. It's the number of possible throws without repetition divided by the total different combinations of dice throw. Here is a handy Combination and Permutation Calculator: http://www.mathsisfun.com/combinatorics/combinations-permutations-calculator.html
Find the possible combinations of rolling a six with two dice: 1 + 5 = 6 5 + 1 = 6 2 + 4 = 6 4 + 2 = 6 3 + 3 = 6 3 + 3 = 6 Six in total. Find the number of possible combinations; Number of Sides on the Dice (6) to power of how many dice (2) = 36 Number of Times the Dice will sum to Six (6 times) -------------------------------------------------- Number of Possible outcomes This will give us 6 out of 36 rolls. Or reduced 1/6 rolls
Assuming of course that we are talking about cubic dice. combinations that make 9: 6&3, 5&4, 4&5, 3&6. There are 4 combinations that make 9. There are 36 possible combination of two dice. So 4/36 is 1/9