100 sq feet = 10 feet x 10 feet, however since it is a rectangular building and not a square one then this is not a solution. There are an infinite number of solutions to this. Possible solutions could be: * 1 ft x 100 ft * 2 ft x 50 ft * 3 ft x 33.3 ft * 4 ft x 25 ft * 5 ft x 20 ft * 6 ft x 16.7 ft * 7 ft x 14.3 ft * 8 ft x 12.5 ft * 9 ft x 11.1 ft
It is impossible to answer the question without knowing what the "64 feet" refers to. The perimeter, or a misstated measure of area.
It is not possible. For example, the prism could be tall and thin, or short and thick, and either way have the same surface area.
You could share what information you did have and then there may be a way to get the missing dimensions. As it is, there is nothing that can be said other than to suggest that you measure them.
The volume of a rectangular prism does not provide enough information to determine its dimensions. It could, for example by 1 cm * 1 cm * 360 cm or 1 cm * 10 cm * 36 cm or 10 cm * 10 cm * 3.6 cm These are just a few of the infinitely many possible answers.
It could be anything.... the question needs to be more specific.
It is impossible to answer the question without knowing what the "64 feet" refers to. The perimeter, or a misstated measure of area.
It is not possible. For example, the prism could be tall and thin, or short and thick, and either way have the same surface area.
You could share what information you did have and then there may be a way to get the missing dimensions. As it is, there is nothing that can be said other than to suggest that you measure them.
The volume of a rectangular prism does not provide enough information to determine its dimensions. It could, for example by 1 cm * 1 cm * 360 cm or 1 cm * 10 cm * 36 cm or 10 cm * 10 cm * 3.6 cm These are just a few of the infinitely many possible answers.
It could be anything.... the question needs to be more specific.
The volume of a rectangular prism does not provide sufficient information to determine its dimensions. The prism could by a cuboid with edges of length cuberoot(384) = 7.27 cm approx. Or it could be a prism with bases of 1 cm * 1 cm and a length of 384 cm, or bases of 1 mm * 1mm and a length of 384 metres or it could be an even narrower longer shape.
It is not possible to answer the question.The area could by a circle with a radius of 1/sqrt(pi) miles. It could be rectangular with one pair of side which is A miles long and the other pair being 1/A miles in length for any non-zero number A. Or it could be any regular or even an irregular shape.
The volume of a rectangular solid with those dimensions is 27 cm3.If we also knew its mass, then we could calculate its density.
If the display uses 100 square cards and each group of 100 volunteers holds up the cards to form complete pictures, then the rectangular arrangement should have dimensions that allow for 100 cards to be displayed. The possible rectangular arrangements could be 10 rows by 10 columns, 20 rows by 5 columns, 25 rows by 4 columns, or any other combination that results in a total of 100 cards.
A rectangular number sequence is the sequence of numbers of counters needed to construct a sequence of rectangles, where the dimensions of the sides of the rectangles are whole numbers and change in a regular way. The individual sequences representing the sides are usually arithmetic progressions, but could in principle be given by difference equations, geometric progressions, or functions of the dimensions of the sides of previous rectangles in the sequence.
The area of a shape does not provide enough information to determine its dimensions. First of all, there is no reason to assume that the area is rectangular in shape. Second, even if it were rectangular, it could be square or extremely long and very narrow.
It is not possible to tell because it could be a squat can with a large radius or a thin tall can.