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The point(s) of intersection must satisfy both equations.

So

2x + k = x2 - 8x - 7

Or, x2 - 10x - 7 - k = 0

The discriminant for this quadratic equation is (-10)2 - 4*1*(-7-k)

= 100 + 28 + 4k

= 128 + 4k

For there to be 2 real distinct points of intersection, discriminant > 0

that is 128 + 4k > 0

4k > -128 so that k > -32.

For there to be a single point of intersection, discriminant = 0 so that k = -32.

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11y ago

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