The point(s) of intersection must satisfy both equations.
So
2x + k = x2 - 8x - 7
Or, x2 - 10x - 7 - k = 0
The discriminant for this quadratic equation is (-10)2 - 4*1*(-7-k)
= 100 + 28 + 4k
= 128 + 4k
For there to be 2 real distinct points of intersection, discriminant > 0
that is 128 + 4k > 0
4k > -128 so that k > -32.
For there to be a single point of intersection, discriminant = 0 so that k = -32.
Yes, of course it is.
No. Two distinct points define a single line.
All lines are defined by two or more distinct points.
It will have end points to be a distinct line segment
Infinitely many if the 3 distinct points are collinear. Otherwise just 1.
discuss the possible number of points of interscetion of two distinct circle
Yes, of course it is.
Yes this true at one point in time
No. Two distinct points define a single line.
All lines are defined by two or more distinct points.
It will have end points to be a distinct line segment
Yes. Every line has an infinite number of distinct points.
No. Two points determine one line, and only one.
By showing your workings.
Infinitely many if the 3 distinct points are collinear. Otherwise just 1.
Five points equals .5 carats where one carat equals 1.00 points.
It takes exactly 2 distinct points to uniquely define a line, i.e. for any two distinct points, there is a unique line containing them.