The magnetic quantum number ( m_l ) can take on integer values ranging from (-l) to (+l), including zero. For ( l = 0 ), ( m_l ) can only be ( 0 ). For ( l = 1 ), ( m_l ) can be (-1, 0, +1). For ( l = 2 ), ( m_l ) can take the values (-2, -1, 0, +1, +2).
(N-1)=(4-1)= N=3 l=0,1,2,3
each get 10 ml
From a 10 ml vial, you can administer 100 injections of 0.1 ml each. This is calculated by dividing the total volume of the vial (10 ml) by the volume of each injection (0.1 ml), resulting in 10 ml ÷ 0.1 ml = 100 injections.
Yes, it would be pz: ml= 0, px: ml=-1 and py: +1
Each 1,000 ml = 1 liter. 9,600 ml = (9,600 / 1,000) = 9.6 liter
The possible values of ml for an electron in a d orbital range from -2 to +2. This corresponds to the five orbitals in a d subshell: dz^2, dx^2-y^2, dxz, dyz, and dxy. Each orbital can hold up to two electrons with opposite spins.
That depends upon how many grid squares you have in total and the largest value you have to represent. Wherever possible, you should arrange that each square that you have to shade represents either a divisor or a simple fraction of all the values you have to represent. With 0.49 ml as one of the values, it is unlikely that the values you will have to represent are all multiples of 0.49 ml; nor are they all likely to be multiples of 0.07 ml. So unless you use 1 grid square to represent 0.01 ml you are going to have to shade a fraction of a grid square. Once you have chosen how much each grid square will represent, or have been given the value to use, divide the 0.49 by this value to find out how many grid square to shade: If each grid square represents 0.01 ml, shade 0.49 ÷ 0.01 = 49 of them If each grid square represents 0.02 ml, shade 0.49 ÷ 0.02 = 24 1/2 of them If each grid square represents 0.04 ml, shade 0.49 ÷ 0.04 = 12 1/4 of them If each grid square represents 0.05 ml, shade 0.49 ÷ 0.05 = 9 4/5 of them If each grid square represents 0.10 ml, shade 0.49 ÷ 0.10 = 4 9/10 of them etc.
(N-1)=(4-1)= N=3 l=0,1,2,3
I have essentially zero ability to answer that without seeing the equation. Another answer: n-1 = 3-1= 2 l=2 ml= -2,-1,0,1,2.
It is 4.2ML.
The range is: 8.7 minus 1.9 = 6.8 ml
The final volume after mixing is 42.2 mL. To find the concentrations of each ion in the final solution: [Na+] = (0.260 M * 15.0 mL + 0) / 42.2 mL [K+] = (0 + 0.200 M * 27.2 mL) / 42.2 mL [SO4^2-] = (0.260 M * 15.0 mL) / 42.2 mL [Cl-] = (0.200 M * 27.2 mL) / 42.2 mL Calculate each concentration using these formulas.
It is 6.8ml, the difference between the lowest and highest numbers.
You get the difference between the highest and lowest values, which are 8.7ml and 1.9ml. So 6.8ml is the range.
The average of the measurements is 4.1 mL. This is calculated by adding up all the measurements and then dividing by the total number of measurements.
n : 2 l : 1 ml : -1, 0, or 1
To calculate the volume of each alcohol drop, you would divide 1 ml by 153 drops. This would give you the volume of each drop in milliliters. The calculation would be: 1 ml / 153 drops = 0.0065 ml per drop.