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I will use the quadratic equation here. By inspection the discriminant shows 2 real roots.

X = -b +/- sqrt(b^2 - 4ac)/2a

a = 1

b = - 3

c = - 2

X = -(-3) +/- sqrt[(-3)^2 - 4(1)(-2)]2(1)

X = 3 +/- sqrt(17)/2

X = [3 +/- sqrt(17]/2

exact answer.

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13y ago
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Q: What are the roots of the equation x squared -3x-2 equals 0?
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