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Use the quadratic equation to find the roots of 2x2-3x-3=0.

a=2, b=-3, c=-3

x =[ -b +- SQRT(b2-4ac)]/2a

=[--3 +- SQRT((-3)2 - 4(2)(-3))]/2*2

= [3+-SQRT(9--24)]/4

so the roots are x = [3+SQRT(33)]/4 and x = [3-SQRT(33)]/4

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Q: What are the roots of the quadratic equation 2X2-3X-3 equals 0?
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