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Use the quadratic equation to find the roots of 2x2-3x-3=0.
a=2, b=-3, c=-3
x =[ -b +- SQRT(b2-4ac)]/2a
=[--3 +- SQRT((-3)2 - 4(2)(-3))]/2*2
= [3+-SQRT(9--24)]/4
so the roots are x = [3+SQRT(33)]/4 and x = [3-SQRT(33)]/4
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