2x + 12x = 14x then include the -9 so the asnwer is 14x-9.
6+(-2x-8)-(-3+12x)-(4y)= 6-2x-8+3-12x-4y=1-14x-4y 1-14x=4y (1-14x)/4=y
12x + 31 = 2x + 1710x = -14x = - 1.4
14x - 14 = 2x + 46 14x - 2x = 46 + 14 12x = 60 x = 5
x^2 + 14x + 40 factorises as (x + 10)(x + 4) so the roots are x = -10, -4.
2x + 12x = 14x then include the -9 so the asnwer is 14x-9.
12x - 14 = 5x12x = 5x + 147x = 14x = 2
x2+12x+36=0 2x+12x+36=0 14x+36=0 14x=-36 x=-36/14 x=-2 4/7
6+(-2x-8)-(-3+12x)-(4y)= 6-2x-8+3-12x-4y=1-14x-4y 1-14x=4y (1-14x)/4=y
If you mean: 3x^2+12x+12 = 0 then it has two equal solutions of -2
That looks like a linear equation (no quadratic or higher terms), so you can expect it to have a single solution. However, actually solving the equation is not difficult; do it, to confirm this.
12x + 31 = 2x + 1710x = -14x = - 1.4
14x - 14 = 2x + 46 14x - 2x = 46 + 14 12x = 60 x = 5
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No, 12x and 14y are not like terms. Like terms are terms that have the same variable raised to the same power. In this case, 12x has a variable x raised to the first power, while 14y has a variable y raised to the first power. Since the variables are different, they are not considered like terms.
expanding bracket is basically multiplying and is used in algebra for example: 2(6x+7x) You multiply everything outstide the bracket with everything inside the bracket for example: 2 x 6x=12x 2 x 7x= 14x so now you have expanded the brackets it looks like: 12x + 14x now simplify to make 26x . And that is how to expand brackets
((14x2-21x)/(24x-16))x((12x-8)/(42x-63))