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-1/2x2 - 1/2x + 6 = 5
Multiply by -2 : x2 + x - 12 = - 10 or x2 + x - 2 = 0
Factorising: (x + 2)(x - 1) = 0
So x + 2 = 0 or x - 1 = 0
therefore, x = -2 or x = 1
What else can I help you with?
What are the solutions to the equation x2 plus 4x-9 equals x plus 1?
x = 2 and x = -5
Solutions for 4x squared plus 4x plus 1 equals 0?
(2x + 1)(2x + 1) or (2x + 1)2 so x = -0.5
How many solutions do the equations 2x - y equals 8 and x plus y equals 1 have?
Only one: (3,-2)
How many real solutions are there to the equation shown below 4x2 plus x - 1 equals 0?
2.
What are the 2 solutions for x plus 8 equals 1?
There's only one solution. [ x = -7 ]
How many solutions does x plus 7 equals 1 have?
2
How many solutions does the following system have x plus y equals 3 and 2x plus y equals 5?
It has 2 solutions and they are x = 2 and y = 1 which are applicable to both equations
If 1 plus 1 equals 2 2 plus 2 equals 22?
no if 1 plus 1 equals 2 then 2 plus 2 equals 4.
What are the solutions to the equation x2 plus 4x-9 equals x plus 1?
x = 2 and x = -5
How many real and imaginary solutions does the equation 2x2 -7x plus 9 equals x plus 1 have?
It has two equal solutions for x which are x = 2 and x = 2
Solutions for 4x squared plus 4x plus 1 equals 0?
(2x + 1)(2x + 1) or (2x + 1)2 so x = -0.5
How many solutions do the equations 2x - y equals 8 and x plus y equals 1 have?
Only one: (3,-2)
How many real solutions are there to the equation shown below 4x2 plus x - 1 equals 0?
2.
What are the 2 solutions for x plus 8 equals 1?
There's only one solution. [ x = -7 ]
What is x2 -2x plus 2 equals 0?
It is a quadratic equation with no real roots or real solutions. In the complex domain, the solutions are 1 +/- i where i is the imaginary square root of -1.
How many solutions does 2x-y equals 8 and x plus y equals 1 have?
2x - y = 8 x + y = 1 These are your two equations. They will have two solutions since you have two variables. The solutions are x=3 and y=-2
How many real solutions are there to the equqtion 4x2 plus x-1 equals 0?
It has 2 real solutions because the discriminant is greater than zero.
