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To solve the equation (20x^2 - 26x + 80 = 0), we can use the quadratic formula (x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}), where (a = 20), (b = -26), and (c = 80). First, we calculate the discriminant: (b^2 - 4ac = (-26)^2 - 4(20)(80) = 676 - 6400 = -5724). Since the discriminant is negative, the equation has no real solutions, but it does have two complex solutions.

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