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The third multiple of 3 is 9 and the fourth multiple of 4 is 16. So 9 multiplied by 16 is 144.
2 multiples of 9, which is 18.
This is a single-equation algebra problem, and can be stated using the variable T to stand for the number of Third Grade students (our answer).The equation is Fifth Grade + Fourth Grade + Third Grade = 33 total members.In terms of T, this is (T+6) + (T) + (T) = 33Which reduces to 3T + 6 = 33 and 3T = 27 and T = 9.There are 9 third-grade students, 9 fourth-grade students, and 15 fifth-grade students = 33.
The answer to that would be 9/10ths
9