7 and 8
The equation for this problem would be x + (x + 2) = 56.After combining the two x's, we get 2x + 2 = 56, then 2x = 54, which brings us to find that x = 27. So, 27 is the first odd integer. Since it is two consecutive odd integers, we need to add 2 to 27, giving us 29. Thus, the two consecutive odd integers whose sum is 56 are 27 and 29.
8 and 7.
Actually the problem does not have a solution with the constraint that the two numbers are consecutive integers. With consecutive integers, one of the integers will be odd and the other one even. An even plus an odd always equals an odd, and you want them to add up to 56, which is an even number. 27.5 + 28.5= 56. steps shown below: x+ (x+1)=56 2x+1 = 56 2x= 56-1 2x= 55 x=55/2 x=27.5 second number is x +1= 27.5+1= 28.5
Your answers are 7 & 8 7 + 8 = 15 7 x 8 = 56
55
7 and 8
The average of the two odd integers is 28. Therefore the two integers are 28-1 and 28+1, i.e 27 and 29.
They are are 7 and 8.
7 and 8?
The numbers are 56 and 58.
7 and 8
56 64 are two positive integers. They do not illustrate the distributive property.
The equation for this problem would be x + (x + 2) = 56.After combining the two x's, we get 2x + 2 = 56, then 2x = 54, which brings us to find that x = 27. So, 27 is the first odd integer. Since it is two consecutive odd integers, we need to add 2 to 27, giving us 29. Thus, the two consecutive odd integers whose sum is 56 are 27 and 29.
8 and 7.
Actually the problem does not have a solution with the constraint that the two numbers are consecutive integers. With consecutive integers, one of the integers will be odd and the other one even. An even plus an odd always equals an odd, and you want them to add up to 56, which is an even number. 27.5 + 28.5= 56. steps shown below: x+ (x+1)=56 2x+1 = 56 2x= 56-1 2x= 55 x=55/2 x=27.5 second number is x +1= 27.5+1= 28.5
The two numbers are either 7 and 8 or -7 and -8.