What are the values of x y and z when the equal terms of 7x plus 11y plus 13z have a sum of 15 and a product of 125 showing work?

Answer 1

If: 7x+11y+13z = 15

Then: 7(15/21)+11(15/33)+13(15/39) = 15 because 5+5+5 =15

So it follows: 7(15/21)*11(15/33)*13(15/39) = 125 because 5*5*5 = 125

Therefore: x = 15/21 y = 15/33 and z = 15/39

Or as: x = 5/7 y = 5/11 and z = 5/13