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f(x) = -4(x + 1)2 + 3

y = -4(x2 + 2x + 1) + 3

y = -4x2 - 8x - 4 + 3

y = -4x2 - 8x - 1 (set y equal to 0 to find the x-intercepts)

0 = -4x2 - 8x - 1

x =[-(-8) ± √[(-8)2 - 4(-4)(-1)]]/2(-4)

x =[8 ± √(64 - 16)]/-8

x =(8 ± √48)/-8

x =(8 ± 4√3)/-8

x = -1 ± -(1/2)√3

x = -1 - (1/2)√3 or x = -1 + (1/2)√3

x ≈ -1 - 0.87 or x ≈ -1 + 0.87

x ≈ -1.87 or x ≈ -0.13

Thus, the two x-intercepts are about -1.87 and -0.13.

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