To find the zeros of the function ( f(x) = x\sqrt{2} + 4x + 8 ), we set the equation equal to zero: ( x\sqrt{2} + 4x + 8 = 0 ). This can be rewritten as ( x(\sqrt{2} + 4) + 8 = 0 ). Solving for ( x ), we get ( x(\sqrt{2} + 4) = -8 ), leading to ( x = \frac{-8}{\sqrt{2} + 4} ). Thus, the zeros of the function are ( x = \frac{-8}{\sqrt{2} + 4} ).
No.
2
4x-14
The answer to the problem of 13 equals -4x plus 9 is x equals -1.
x^2 plus 4 = 0x^2 = -4square root both sidesx = the square root of -4x = 2i
x = 3
No.
2
4x-14
The answer to the problem of 13 equals -4x plus 9 is x equals -1.
x^2 plus 4 = 0x^2 = -4square root both sidesx = the square root of -4x = 2i
4x plus 7 plus 3x equals 19 plus xx = 2
(9,3)
4x+32=-4x+16x4x+32=12x-4x -4x32=8x/8 /84=x
-4x + 4y = 1
if -4x+6=38 what x=
x = -½