The minimum value of the secant and cosecant is ' 1 '. There are no zeros.
No. Vertical lines are not.
Billion has 9 zeros Trillion has 12 zeros Quadrillion has 15 zeros Quintillion has 18 zeros Sextillion has 21 zeros Septillion has 24 zeros Octillion has 27 zeros Nonillion has 30 zeros Decillion has 33 zeros Undecillion has 36 zeros Duodecillion has 39 zeros Tredecillion has 42 zeros Quattuordecillion has 45 zeros Quindecillion has 48 zeros Sexdecillion has 51 zeros Septendecillion has 54 zeros Octodecillion has 57 zeros Novemdecillion has 60 zeros Vigintillion has 63 zeros Googol has 100 zeros. Centillion has 303 zeros (except in Britain, where it has 600 zeros) Googolplex has a googol of zeros
Only if the two functions really represent the same function.
a) A circle is not the graph of a function. b) A circle is not linear.
The zeros of a polynomial represent the points at which the graph crosses (or touches) the x-axis.
The minimum value of the secant and cosecant is ' 1 '. There are no zeros.
sin(x) and cos(x).
in 2's Complement there is only one zero: All zeros In 1's Complement there are two zeros: All zeros, and All ones ("negative" zero). So you have one less signed number you can represent with the same amount of bits. For example, with 8 bits, with 2's Complement you can represent -128 to +127 while with 1's complement you can only represent -127 to +127.
No. Vertical lines are not.
In the context of measuring weight in grams, the term "zero" does not have a numerical value. Grams are a unit of mass in the metric system, and they represent a specific quantity of matter. Therefore, the concept of "zeros" does not apply to grams as it would in a numerical value or calculation.
It's actually quite hard to graph complex numbers - you would need a four-dimensional space to graph them adequately. I believe it's more convenient to find zeros analytically for such functions.
No just a fictitious number made up to represent any huge number some try to argue this fact but they are most certainly wrong Just so you know, here's the list of "named illions": Billion has 9 zeros Trillion has 12 zeros Quadrillion has 15 zeros Quintillion has 18 zeros Sextillion has 21 zeros Septillion has 24 zeros Octillion has 27 zeros Nonillion has 30 zeros Decillion has 33 zeros Undecillion has 36 zeros Duodecillion has 39 zeros Tredecillion has 42 zeros Quattuordecillion has 45 zeros Quindecillion has 48 zeros Sexdecillion has 51 zeros Septendecillion has 54 zeros Octodecillion has 57 zeros Novemdecillion has 60 zeros Vigintillion has 63 zeros Googol has 100 zeros. Centillion has 303 zeros (except in Britain, where it has 600 zeros) Googolplex has a googol of zeros the original answer was wrong From Gazzen, from Latin "earthly edge", or end of the earth, abbreviated to gaz (literally 28810 ancient Greek miles, been one full revolution of the globe) So how much is a Gazillion? a Gazillion has (28810 x 3) zeros thus a Gazillion has 86430 zeros
The zeros of f(x), a function of the variable x, are those values of x for which f(x) = 0. These are points at which the graph of f(x) crosses (or touches) the x-axis. Many functions will do so several times over the relevant domain and the values (of x) are the distinct zeros.
A structure is a different from a class in the sense that a class can represent data elements as well as their associated functions whereas a structure can represent only data elements,, not their associated functions.
Just 1. The zeros before the 5 are just placeholders, not significant figures. However, if the number were 0.0500, then there would be 3 sig figs. This is because the extra zeros represent greater accuracy in the measurement.
1000