(6375,1)(2125,3)(1275,5)(425,15)(375,17)(255,25)(125,51)(85,75)
Assuming you want all factors of a number: 1) Split a number into prime factors. 2) Combine the prime factors in all possible ways. To get the prime factors, you can systematically try out dividing the number by prime numbers, up to the number's square root (once the square of the prime number you try out is greater than the original number, you need not continue). For example, to find out prime factors of numbers up to 120, you only need to try dividing by 2, 3, 5, 7.
I suspect that something very important is missing from your question. It would go between the words "write" and "as", and it would be a number. The answer to the question would be a positive whole number greater than ' 1 '.
There are several ways for such a number to be constructed: It can be the seventh power of a prime. It can be the third power of a prime multiplied by the third power of another prime. It can be the third power of a prime multiplied by the first power of two other primes. It can be the first power of three different primes.
Factor trees are ways of notating the process of finding the prime factorization of a given composite number and, as such, should result in an identifiable string of prime factors.
According to Wolfram Alpha, its prime factors are 11×79×2556067. (To get all of its factors, you can combine the prime factors in different ways.)
(6375,1)(2125,3)(1275,5)(425,15)(375,17)(255,25)(125,51)(85,75)
Divide it by each prime number which does not have remainder.
two possible ways 1 and the other number or the number an 1
Assuming you want all factors of a number: 1) Split a number into prime factors. 2) Combine the prime factors in all possible ways. To get the prime factors, you can systematically try out dividing the number by prime numbers, up to the number's square root (once the square of the prime number you try out is greater than the original number, you need not continue). For example, to find out prime factors of numbers up to 120, you only need to try dividing by 2, 3, 5, 7.
I suspect that something very important is missing from your question. It would go between the words "write" and "as", and it would be a number. The answer to the question would be a positive whole number greater than ' 1 '.
As a product of its prime factors: 2*47 = 94
One subset is prime numbers, since their factors are only 1 and the number itself. Other than that, there are many ways to end up with an even number of factors. The general equation for the number of factors is (p1+1)(p2+1) ... (p3 + 1) where the p values are the exponents of the prime factors of the number. So, as long as at least one prime factor is represented oddly (i.e., there is only 1, 3, 5... so on factors of that value in the prime factorization), then the number will have an even number of factors.
I'm not sure what you mean. But the factorization of a composite number into prime factors is unique, up to the ordering of the primes.
There are several ways for such a number to be constructed: It can be the seventh power of a prime. It can be the third power of a prime multiplied by the third power of another prime. It can be the third power of a prime multiplied by the first power of two other primes. It can be the first power of three different primes.
There are two ways in which the factors can be given. You are given all the prime factors (and their multiplicity). In that case simply multiply them all together. Or You are given each factor. In this case, the biggest of these is the number.
There's a lot of different ways to notate the process (factor trees, rainbows, fireworks, division ladders, etc.) but the process itself is essentially the same. Divide a composite number by prime numbers until all the factors are prime.