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This can be solved with algebra and simultaneous equations:

  • x + y = 100, which we rearrange to get Y = 100 - X
  • x - y = 6 , which we rearrange to get X = 6 + Y
  • replacing X in the first equation with 6+Y in the second equation gives us:
  • y = 100 - (6 + Y) ====> Y = 100 - 6 - Y ====> Y = 94 - Y ====> 2Y = 94 ===> Y = 47
If Y is 47 than X has to be 53 giving us:
  • 53 + 47 = 100
  • 53 - 47 = 6
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Q: What are two numbers with the sum of 100 and the difference of 6?
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