Let the number be 'm' & 'n'
Hence
Sum = m + n = -5
Product = mn = 4
Algebraically rearrange the product to m = 4/n
Substitute into the Sum
(4/n) + n = -5
Multiply through by 'n'
Hence
4 + n^2 = -5n
n^2 + 5n + 4 = 0
It is not in Quadrtatic form . to solve.
Hence
(n - 1)(n - 4) = 0
n = -1 & n = -4
Are the two numbers.
4 and 5
5 and 4. 5x4=20 (product) 5+4=9 (sum)
-4 and -2
8 and 4
4 and 6 do.
4 and 1.
4 and 5
5 and 4. 5x4=20 (product) 5+4=9 (sum)
-4 and -6
4 and -6.
-4 and -2
4 and 6 do.
They are: -3 and -4
8 and 4
10, -9 sum is 1 product is -90. any two numbers one positive one negative, positive has to be larger
13
The number are 2 and 4