Let the number be 'm' & 'n'
Hence
Sum = m + n = -5
Product = mn = 4
Algebraically rearrange the product to m = 4/n
Substitute into the Sum
(4/n) + n = -5
Multiply through by 'n'
Hence
4 + n^2 = -5n
n^2 + 5n + 4 = 0
It is not in Quadrtatic form . to solve.
Hence
(n - 1)(n - 4) = 0
n = -1 & n = -4
Are the two numbers.
−4 + −1 = −5
−4 × −1 = 4
4 and 5
5 and 4. 5x4=20 (product) 5+4=9 (sum)
4 and 6 do.
-4 and -2
8 and 4
4 and 1.
4 and 5
5 and 4. 5x4=20 (product) 5+4=9 (sum)
4 and -6.
-4 and -6
They are: -3 and -4
-4 and -2
4 and 6 do.
8 and 4
Sum = Addition 5 + 4 = 9 Product = Multiplication 5 x 4 = 20 The two numbers are 5 and 4.
numbers -4 and 1 1 and -4 1 and -4
-4 and +12