To be a linear equation, the equation must be set equal to Y. Also, it can't have any square roots, or any variables on the bottom of a fraction.
In general, the terms of a linear equation must be either first-degree polynomials with respect to the variables, constants, or products of the two. This disallows terms involving trigonometric, logarithmic, exponential, hyperbolic, and power expressions (except for the power of 1) and their inverses.
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By definition, there cannot be a simultaneous equation that cannot be solved, there must be a set of simultaneous equations. It is important to realise that simultaneous equations need not be linear.It is simple to devise a pair of linear equations that are inconsistent:x + y = 1 and x + y = 2There is no solution. Graphically, the two lines are parallel.Another possibility isx + y = 1 and 2x + 2y = 2In this case there are an infinite number of solutions. Graphically, the two lines are coincidet, so that every point on the common line is a solution. There is, therefore, no unique solution.Yet another situation can arise when the domain of the equations is restricted.For example,x2 + y2 = -1 where x and y are real along with any other equation in x and y.
linear?
Well I cant graph it for you but its a linear line some points would be (0,-1) (1,-2) (2,-3)(3,-4) (-1,0) (-2,1) (-3,2) and so on
The equation you provided, 3x - y = 1, cannot be solved for any specific values of x and y without additional information. It is a linear equation in two variables, so it represents a straight line on a graph. To find a solution, you would need another equation or constraint.
For vertical lines, when you try to figure out the slope, you get zero in the denominator - in other words, a division by zero.