Both 7 and 16 can go into their least common multiple (LCM), which is 112. This means that any multiple of 112, such as 112, 224, or 336, can be evenly divided by both 7 and 16. Additionally, they can both go into any number that is a common multiple of both.
2X + 7 = 5X + 16 subtract 2X from both sides 7 = 3X + 16 subtract 16 from both sides -9 = 3X divide both sides by 3 -3 = X check 2(-3) + 7 = 5(-3) + 16 1 = 1 checks
7, R 16
7/16 - 1/4... Make the 1/4 into 16ths by multiplying BOTH numbers by 4 - You now have... 7/16 - 4/16 which is 3/16
14 = 2*7 49 = 7*7 So 1, -1, 7, -7 all go into both 14 and 49.
32
both these number go into the number 112
16 and 13 both go into any multiple of 208 .
2X + 7 = 5X + 16 subtract 2X from both sides 7 = 3X + 16 subtract 16 from both sides -9 = 3X divide both sides by 3 -3 = X check 2(-3) + 7 = 5(-3) + 16 1 = 1 checks
16 and remainder 2
both numerator and denominator are divisible by 16 so 16/112 = 1/7
7 x 16 = 112
7, R 16
It is an equation in the form of: n/16 +7 = 10 and the value of n is 48
7/16 - 1/4... Make the 1/4 into 16ths by multiplying BOTH numbers by 4 - You now have... 7/16 - 4/16 which is 3/16
n + 16 = 9 n + 16 - 16 = 9 -16 (add 16 to both sides, the equation remains same) n + 0 = -7 n = -7
14 = 2*7 49 = 7*7 So 1, -1, 7, -7 all go into both 14 and 49.
2r - 7 = 9 (+7) (+7) >> add 7 to both sides so that only 2r is on that side 2r = 16 2r/2 = 16/2 >> divide both sides by 2 to isolate the variable r=8 >>16 divided by 2 is 8 which is your answer