2X + 7 = 5X + 16 subtract 2X from both sides 7 = 3X + 16 subtract 16 from both sides -9 = 3X divide both sides by 3 -3 = X check 2(-3) + 7 = 5(-3) + 16 1 = 1 checks
The number of times 7 can go into 16 is determined by dividing 16 by 7. The quotient is the whole number result of the division. In this case, 16 divided by 7 equals 2 with a remainder of 2. Therefore, 7 can go into 16 two times with a remainder of 2.
7, R 16
7/16 - 1/4... Make the 1/4 into 16ths by multiplying BOTH numbers by 4 - You now have... 7/16 - 4/16 which is 3/16
32
16 and 13 both go into any multiple of 208 .
both these number go into the number 112
2X + 7 = 5X + 16 subtract 2X from both sides 7 = 3X + 16 subtract 16 from both sides -9 = 3X divide both sides by 3 -3 = X check 2(-3) + 7 = 5(-3) + 16 1 = 1 checks
16 and remainder 2
The number of times 7 can go into 16 is determined by dividing 16 by 7. The quotient is the whole number result of the division. In this case, 16 divided by 7 equals 2 with a remainder of 2. Therefore, 7 can go into 16 two times with a remainder of 2.
both numerator and denominator are divisible by 16 so 16/112 = 1/7
7 x 16 = 112
7, R 16
It is an equation in the form of: n/16 +7 = 10 and the value of n is 48
7/16 - 1/4... Make the 1/4 into 16ths by multiplying BOTH numbers by 4 - You now have... 7/16 - 4/16 which is 3/16
32
n + 16 = 9 n + 16 - 16 = 9 -16 (add 16 to both sides, the equation remains same) n + 0 = -7 n = -7