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Make a table, and start with 1. Find a number that multiplies 1 to give a product of 80. Than try 2, 3, 4, 5... If you cannot find a number that multiples to produce a product, move to the next term. Once the terms repeat, you have found all the factors/multiples.

1 x 80 = 80

2 x 40 = 80

3 x ??? <-- no whole number factor exists

4 x 20 = 80

5 x 16 = 80

6 x ??? <-- no whole number factor exists

7 x ??? <-- no whole number factor exists

8 x 10 = 80

9 x ??? <-- no whole number factor exists

10 x 8 = 80 (this is repeated 8 x 10, so we have found all the factors)


Therefore, your answer is:

1 x 80, 2 x 40, 4 x 20, 5 x 16, and 8 x 10 to get 80.


The factors are (extra information):

1, 2, 5, 8, 10, 16, 20, 40, 80


Additionally, you can always multiply a square root of a number by the same square root of a number to get a number (more extra information):

i.e.: (√80)(√80) =√802 = 80

Technically, it's plus or minus 80, but√80 is a non-integerfactor of 80 regardless.


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12y ago

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