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Here are two formulae for centripetal acceleration:

a = v2 / r (speed squared divided by the radius)

a = omega2r (angular velocity squared, times the radius)


The second formula seems simpler to use in this case. Just convert the angular speed to radians per second first. Remember that 1 minute = 60 seconds, and one revolution/second = 2 x pi radians/second.


Oh, and you have to convert feet to meters, as well. 1 foot = 0.3048 meters.


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Q: What centripetal acceleration in meters per second squared if it has a twenty eight feet radius and is rotated with an angular speed of ten rpm?
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Related questions

How is the radius of rotation related to the centripetal force and angular velocity?

Assuming that angles are measured in radians, and angular velocity in radians per second (this simplifies formulae): Radius of rotation is unrelated to angular velocity. Linear velocity = angular velocity x radius Centripetal acceleration = velocity squared / radius Centripetal acceleration = (angular velocity) squared x radius Centripetal force = mass x acceleration = mass x (angular velocity) squared x radius


What is centripetal acceleration equation?

Two equations are commonly used for the magnitude of the centripetal acceleration (the direction of the acceleration is towards the center): a = v squared / r a = omega squared x r where: * v is the linear speed * omega is the angular speed (in radians/second) * r is the radius


If you increase the radius of circular motion then what is the centripetal acceleration?

That depends what you will remain constant: the angular velocity, or the speed. Here are two formulae that can help you decide: acceleration = speed squared / radius, and acceleration = angular velocity squared times radius. Angular speed should be measured in radians in this case. Angular speed is equal to 2 x pi x (revolutions per second). From the above formulae, it clearly follows that: (a) If you maintain the speed constant (and thereby reduce angular speed, a larger radius means less centripetal acceleration. (b) If you maintain the angular speed constant (and thereby increase the speed), a larger radius means more centripetal acceleration.


How does the centripetal force with the speed of rotation of the body with constant mass and radius of rotation?

You can calculate the centripetal ACCELERATION with one of these formulae: acceleration = velocity squared / radius acceleration = omega squared x radius Acceleration refers to the magnitude of the acceleration; the direction is towards the center. Omega is the angular speed, in radians per second. To get the centripetal FORCE, you can use Newton's Second Law. In other words, just multiply the acceleration by the mass.


What is the relationship between radial force and angular velocity squared?

By radial force, we can assume you mean centripetal force Centripetal force = (Mass)(Radius)(Angular velocity)2


How do you calculate the centripetal acceleration of an object?

ac = v2/r, where the variables are: * 'a' is the centripetal acceleration in metres per second per second; * 'v' is the tangential velocity in metres per second; and * 'r' is the radius of motion in metres.


How does centripetal acceleration depend upon the object's speed and the radius of the circle?

The centripetal acceleration is equal to velocity squared over radius. a=v^2/r


What is the centripetal acceleration of an object being swung on a string with a radius of 3 meters at a velocity of 4 meters per second?

Use the formula for centripetal acceleration: velocity squared / radius.


How do they affect the centripetal force?

If an object moves in a circle, the centripetal acceleration can be calculated as speed squared divided by the radius. The centripetal force, of course, is calculated with Newton's Second Law: force = mass x acceleration. Therefore, the centripetal force will be equal to mass x speed2 / radius.


What is toward the center of uniform centripetal motion?

acceleration, a = velocity squared / radius(a = v^2 / r)


What is the unit of centripetal acceleration?

The unit of centripetal acceleration is meters per second squared (m/s^2). It represents the change in velocity per unit time in the direction towards the center of the circular motion.


What is the tangential velocity and centripetal acceleration of the earth moving around the sun?

Tangential velocity squared is GMs/r and velocity v =29814m/s and the centripetal acceleration is v2/r= 5.928 E-3 m/s2