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Given any number it is easy to find a rule based on a polynomial of order 6 such that the first six numbers are as listed in the question and the next is the given number. There are also non-polynomial solutions.
The simplest pule, using a polynomial of degree 5 is
T(n) = (43*n^5 - 740*n*4 + 4765*n^3 - 14140*n^2 + 19072*n - 8880)/120 for n = 1, 2, 3, ...
Accordingly, the next term is 101.
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