The sequence appears to follow a pattern based on multiplying the previous number by an increasing power of its position in the sequence. Specifically, 3 × 2 = 6 (then add 2 to get 8), 8 × 7 + 7 = 63, and 63 × 63 + 63 = 3968. Continuing this pattern, the next number would be 3968 × 3968 + 3968, resulting in a very large number. The exact calculation will depend on the specific formula you use, but the next term is derived from the same multiplication and addition pattern.
3968. The formula is the starting number squared, minus 1 (2*2-1=3...3*3-1=8....8*8-1=63..... 63*63-1=3968)
2 Add 1 to the number and then take the square root. 3968 + 1 = 3969 : √3969 = 63 63 + 1 = 64 : √64 = 8 8 + 1 = 9 : √9 = 3 3 + 1 = 4 : √4 = 2.
2 3 8 63
15745023
2
2 because sqrt(n+1) is the series.
63
63
129, 255, 513, 1023
35, 48, 63
500
11 comes next.