The sequence appears to follow a pattern based on multiplying the previous number by an increasing power of its position in the sequence. Specifically, 3 × 2 = 6 (then add 2 to get 8), 8 × 7 + 7 = 63, and 63 × 63 + 63 = 3968. Continuing this pattern, the next number would be 3968 × 3968 + 3968, resulting in a very large number. The exact calculation will depend on the specific formula you use, but the next term is derived from the same multiplication and addition pattern.
63
The series alternates between two patterns: one where numbers are multiplied by 3 and then reduced (18 to 27 to 36) and another where numbers are multiplied by 4 and then reduced (81 to 72 to 63). Following this pattern, the next number after 36 (from the first sequence) would be 45 (36 multiplied by 1.25), and after 63 (from the second sequence), the next number would be 54 (63 reduced by 9). Thus, the next number in the series is 45.
63
11 comes next.
63, 102, 165...
3968. The formula is the starting number squared, minus 1 (2*2-1=3...3*3-1=8....8*8-1=63..... 63*63-1=3968)
2 Add 1 to the number and then take the square root. 3968 + 1 = 3969 : √3969 = 63 63 + 1 = 64 : √64 = 8 8 + 1 = 9 : √9 = 3 3 + 1 = 4 : √4 = 2.
2 3 8 63
2
15745023
2 because sqrt(n+1) is the series.
63
The series alternates between two patterns: one where numbers are multiplied by 3 and then reduced (18 to 27 to 36) and another where numbers are multiplied by 4 and then reduced (81 to 72 to 63). Following this pattern, the next number after 36 (from the first sequence) would be 45 (36 multiplied by 1.25), and after 63 (from the second sequence), the next number would be 54 (63 reduced by 9). Thus, the next number in the series is 45.
63
129, 255, 513, 1023
35, 48, 63
500