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4+5 = 9 42+52 = 41
4 and 5 4 + 5 = 9 42 + 52 = 16 + 25 = 41
The additive inverse of 41 is -41. An additive inverse is the number that will make the sum equal zero.
The sum of the squares of two consecutive positive numbers is 41.What is the smaller number?Improved Answer:-It is 4 because 42+52 = 41
16 + 25 = 41