The maximum value represented in a 32-bit unsigned word is 232-1 = 4,294,967,295, so you can represent all numbers with 9 decimal places and some numbers with 10 decimal places in 32-bits. log(232-1) = 9.632959861 is the true answer.
It is 1 foot, exactly as in the question. Decimal refers to counting in tens: it is the way in which we normally represent numbers, with the place value of each digit being ten times the place value of the digit to its right. A decimal representation does not need a decimal point and decimal certainly does not imply the metric or SI system of measurement.
The difference is that all whole numbers are decimal numbers, but not all decimal numbers are whole numbers. For example a whole number such as 1 is a decimal number but a decimal number such as 1.5 is not a whole number.
The only two numbers that represent a binary digit are 0 and 1
-1
It is not possible. A Byte is 8 bits, the largest possible 8 bit number is '11111111' which is only 255 (in normal decimal numbers).
Binary can only be 1 & 0. Decimal numbers have a dot in them. Binary numbers use only 2 symbols (0 and 1) to represent different numbers, while decimal numbers use 10 symbols (0 to 9) to represent different numbers. check the below link for more.
What needs to be undestood is that all data is represented by numbers in binary form. Each binary digit (a single 1 or 0) is called a bit, and 1 byte is 8 bits, the amount needed to represent any number between 0 and 255. Therefore 1 byte is equivalent to 1 letter, number or punctuation character.
255 is the largest decimal number. 1 byte (8 bits) can store 256 *values* (0-255).
A BCD digit only uses the binary patterns that represent decimal numbers, ie 0000 - 1001; this requires 4 bits (1 nybble) so there can be 2 BCD digits to a byte. Therefore in 3 bytes there can be 3 × 2 = 6 BCD digits. The largest BCD digit is 1001 = 9. Assuming non-signed, the maximum 3 byte BCD number is 999,999.
When a bit is turned on, it represents a "1". When it is turned off, it represents a "0". The exact value depends on where the bit is within the byte it is part of. In the binary number 0000 0001, the last bit is set to 1 and represents the number 1. In the binary number 0000 0010, the second to last bit is set to 1, which corresponds to the "2's" place relative to decimal numbers. In the binary number 0000 1000, the bit that is set to 1 represents the value "8" in decimal numbers.
1 million < 165 so 6 digits would be enough.
The maximum value represented in a 32-bit unsigned word is 232-1 = 4,294,967,295, so you can represent all numbers with 9 decimal places and some numbers with 10 decimal places in 32-bits. log(232-1) = 9.632959861 is the true answer.
A byte is group of 8 bits. 128 64 32 16 8 4 2 1 1 1 1 1 1 1 1 = 255 Which in binary can represent a number up to 255. Larger numbers are represented by grouping bytes together. The central processor can handle complete bytes at time, each number represents a command.
It is a collection of eight bits which represent one character. Each bit can have the value of 0 or 1, zero or one. A byte has 256 possible combinations of 0's and 1's. In most programming languages and applications, these combinations are assigned values or functions. In ASCII, 00101010 (42 in decimal) is the * symbol. Number 189,(10111101 in ASCII) is ½ and 241 is ñ. There are other uses and definitions of a byte, including how many bits are in one.
Boolean data type usually requires only 1 byte, because it represent only 1 of 2 possible values: true or false, which is represented as 1 or 0, so only 1 byte is needed.
There are 8 bits in a byte. Bits are a digit in a binary number. Binary is a number system that only has 2 symbols (0 and 1) that can be used to represent a number, as opposed to the usual decimal system that we're used to, which has 10 symbols (0, 1, 2, 3, 4, 5, 6, 7, 8, and 9). In computers, all data is stored as a series of 8-bit binary numbers.