1, 3, 9, 27, 81
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Yes, because 9x9=81 9 divides into 3 three times 3x3=9 So if 9 is a factor of 81, then so must 3. 81/3= 27
If n is any prime number and a² is divisible by n, then n will also divide a. Consider that 'n' exists as a prime number. If n divides a² then n also divides a. Let, n = 3 and a = 9 a² = 9² a² = 81 Here , 81/3 = 27 n divides a² Now, 9/3 = 3 Here, n also divides a.
The Greatest Common Divisor of two numbers is the largest number that will divide into both evenly. For example, although 27 and 81 are both divisible by 3, it wouldn't be the greatest common divisor, because 27 divides into 81 evenly as well: the greatest common divisor of 27 and 81 is 27.
The greatest common factor (GCF) of two numbers is the largest number that divides both numbers without leaving a remainder. To find the GCF of 81 and 256, you can use prime factorization. Prime factorizing 81 gives you 3^4, and prime factorizing 256 gives you 2^8. The common factors between 81 and 256 are 1, 3, and 9. Therefore, the GCF of 81 and 256 is 9.
It is 81*81*81. Which is 531,441.