9 and 13 both go into 117.
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The only number that can go into both 9 and 13 without leaving a remainder is 1. This is because both 9 and 13 are prime numbers, meaning they are only divisible by 1 and themselves. Therefore, 1 is the only common factor that can evenly divide both 9 and 13.
Not evenly.
9/13 is already in simplest form. 13 is prime, it can't be divided by anything.
Answer: y= -1 Solution: 4 - 2 y = 7 y + 13 subtract 7 y from both sides: 4 - 2 y - 7 y = 7 y + 13 - 7 y 4 - 9 y = 13 subtract 4 form both sides: 4 - 4 - 9 y = 13 - 4 - 9 y = 9 now divide both sides by - 9: -9 y / - 9 = 9 /-9 y = -1
13 times 11 = 143.So they both go into any integral multiple of 143.