The only number that can go into both 9 and 13 without leaving a remainder is 1. This is because both 9 and 13 are prime numbers, meaning they are only divisible by 1 and themselves. Therefore, 1 is the only common factor that can evenly divide both 9 and 13.
Not evenly.
9/13 is already in simplest form. 13 is prime, it can't be divided by anything.
Answer: y= -1 Solution: 4 - 2 y = 7 y + 13 subtract 7 y from both sides: 4 - 2 y - 7 y = 7 y + 13 - 7 y 4 - 9 y = 13 subtract 4 form both sides: 4 - 4 - 9 y = 13 - 4 - 9 y = 9 now divide both sides by - 9: -9 y / - 9 = 9 /-9 y = -1
13 times 11 = 143.So they both go into any integral multiple of 143.
Well, honey, 13 and 9 both go into numbers that are multiples of both 13 and 9. So, the numbers that both 13 and 9 go into are the common multiples of 13 and 9, like 117. Hope that clears things up for you, darling.
The only number that can go into both 9 and 13 without leaving a remainder is 1. This is because both 9 and 13 are prime numbers, meaning they are only divisible by 1 and themselves. Therefore, 1 is the only common factor that can evenly divide both 9 and 13.
There are 13.
16 and 13 both go into any multiple of 208 .
They both go into 1440, for example.
4
Not evenly.
To determine how many times 13 can go into 48, we divide 48 by 13. The quotient is 3 with a remainder of 9. Therefore, 13 can go into 48 three times with a remainder of 9.
To find out how many times 13 can go into 119, you would divide 119 by 13. The result is 9, with no remainder. This means that 13 can go into 119 exactly 9 times.
36
9/13 is already in simplest form. 13 is prime, it can't be divided by anything.
Answer: y= -1 Solution: 4 - 2 y = 7 y + 13 subtract 7 y from both sides: 4 - 2 y - 7 y = 7 y + 13 - 7 y 4 - 9 y = 13 subtract 4 form both sides: 4 - 4 - 9 y = 13 - 4 - 9 y = 9 now divide both sides by - 9: -9 y / - 9 = 9 /-9 y = -1