The point where the diagonals meet.
A square, rhombus or a kite
A square, a rhombus and a kite all have diagonals that are perpendicular and meet each other at right angles.
-- Draw both diagonals. -- They intersect (meet and cross) at the midpoint of the square.
Yes because the 4 corners of a square are perpendicular in that they meet at right angles and also the diagonals of a square are perpendicular
The point where the diagonals meet.
A square, rhombus or a kite
Where the diagonals meet. Also where the perpendicular bisectors of the sides meet.
A square, a rhombus and a kite all have diagonals that are perpendicular and meet each other at right angles.
im a pretty square
-- Draw both diagonals. -- They intersect (meet and cross) at the midpoint of the square.
A square if I'm correct
A rectangle is a rhombus when its diagonals meet vertically so, when its diagonals are vertical to each other. Actually, this happens only when it's a square!
Yes because the 4 corners of a square are perpendicular in that they meet at right angles and also the diagonals of a square are perpendicular
Their diagonals are mutually perpendicular - that is, they meet at right angles.
A square is a plane (flat) shape whose boundaries are four straight lines of equal length such that these lines meet, in pairs, at four points (vertices). At these vertices they form angles of 90 degrees. The diagonals of the square are straight lines joining opposite vertices. These diagonals meet one another. The given statement means that the angles formed at the crossing points of the diagonals measure 90 degrees.
No, if they did the shape would be a square. The angle is more than 90 degrees.