yes. any thing you have on the right side of the decimal point(.) is a decimal:)
first you list the numbers in order then eliminate the numbers from the left side then right side until you get to the middle. If you do not find the middle then you add the 2 numbers and divide by 2
I have no idea what you mean with "right side". If you mean "straight side", it is normally implied that in a polygon, such as an octagon, ALL sides are straight.
They are on the right hand side of the number line.
The longest side of a triangle, or the side across from the right angle.
You find the dirty beaker inside the Steamworks Museum when you go all the way to the top right side.
yes. any thing you have on the right side of the decimal point(.) is a decimal:)
There is a very old Dirty Beaker in the Steamworks Museum (far upper right). Use the machines and climb the vines to reach the beaker. You need this at the Greenhouse in the Laboratory (Production zone, right side of the island).
Left side
When a pattern refers to the "right side" of your work, they mean the side that is the front. The side that is the back will be the "wrong" side.
In word processing it means that the line is anchored at the right end, which can be good for numbers and some text. In general it means the item is lined up on the right side, or in tight.
In word processing it means that the line is anchored at the right end, which can be good for numbers and some text. In general it means the item is lined up on the right side, or in tight.
A
You measure angles from either side of the protractor. One set of numbers measures from the left side, the other measures from the right side.
The marble will have the motion of the person who dropped it (I assume you mean by 'dropped' that it is not thrown by the person, just dropped), whilst I assume the beaker is stationary. I also assume the person is moving horizontally and the beaker is upright. Therefore the marble will arrive in the beaker with some sideways velocity and will strike the side of the beaker with a horizontal component of velocity as well as a vertical component. I should think it will spin round the beaker a few times before coming to rest, it might even bounce right out. You can't predict this exactly without some more information.
first you list the numbers in order then eliminate the numbers from the left side then right side until you get to the middle. If you do not find the middle then you add the 2 numbers and divide by 2
Stamped on the right side of the hitch.