Find any real number, X, that is greater than or equal to sqrt(120) = 10.96 (approx). Clearly, since X can be infinitely large, there are infinitely many possible values for X. Let Y = 120/X. [It can be shown that Y is always less than X so that each {X,Y} pair is distinct.]
Then XY = X*(120/X) = 120.
Thus there are infinitely many possible answers to the question.
One such is 72 and 120/72, that is 72 and 1.66... (recurring).
120
1.5 x 120 = 180
60x20=120 30x40=120
Just multiply 0.8 x 120.
-1 and -120
94.8. Just multiply .79 by 120.
120
12
to get the two sums of 120 you multiply twenty times six (20x6=120)
change 17.5% into a decimal and than multiply by 120
You multiply the percentage by 120, and divide the result by 100.
Divide 48 by 120 then multiply by 100