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Find any real number, X, that is greater than or equal to sqrt(120) = 10.96 (approx). Clearly, since X can be infinitely large, there are infinitely many possible values for X. Let Y = 120/X. [It can be shown that Y is always less than X so that each {X,Y} pair is distinct.]
Then XY = X*(120/X) = 120.
Thus there are infinitely many possible answers to the question.
One such is 72 and 120/72, that is 72 and 1.66... (recurring).
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