That's going to depend heavily on the values of 'x' and 'y',
neither of which is revealed in the question.
To solve for x, you will need to set the two expressions equal to each other: (x - 3)/4 = (x + 3)/7. Cross multiply to get 7(x - 3) = 4(x + 3). Expand and solve for x to get 7x - 21 = 4x + 12. Simplify to get 3x = 33, and then divide by 3 to find x = 11. So, x equals 11.
"x" would equal 1 because 7/1 is 7 minus 2 equals 5 and 3/1 is 3 plus or + 2 is 5.
x/35 = 3/7 => x = 3/7 *35 = 3 * (35/7) = 3*5 = 15
1 x 3 x 3 x 7 x 7
You can produce an infinite number of ratios that are equal 3:7. You can do this by simply multiplying both 3 and 7 by the same number, so for example: 3 x 2:7 x 2 6:14 = 3:7 3 x 5:7 x 5 15:35 = 3:7
4/7 x 3/4 is 3/7
To solve for x, you will need to set the two expressions equal to each other: (x - 3)/4 = (x + 3)/7. Cross multiply to get 7(x - 3) = 4(x + 3). Expand and solve for x to get 7x - 21 = 4x + 12. Simplify to get 3x = 33, and then divide by 3 to find x = 11. So, x equals 11.
7
3/5 x 7 = 4 1/5 or 4.2
x= 10.5 3/x = 2/7 so multiplying by 7 this is the same as 21/x =2. Multiply by x to get 21=2x. Divide by 2 to get 10.5 = x
"x" would equal 1 because 7/1 is 7 minus 2 equals 5 and 3/1 is 3 plus or + 2 is 5.
1/3 x 6/7 = 6/21 = 2/7 The reciprocal is 7/2 1/3 x 7/6 = 7/18 The reciprocal is 18/7
x = 3 and x = 7.x = 3 and x = 7.x = 3 and x = 7.x = 3 and x = 7.
3 x 3 x 3 over 3 x 3 x 7 reduces to 3 over 7
3
3 x 3 x 7 x 7 = 441
x/35 = 3/7 => x = 3/7 *35 = 3 * (35/7) = 3*5 = 15