That's going to depend heavily on the values of 'x' and 'y',
neither of which is revealed in the question.
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To solve for x, you will need to set the two expressions equal to each other: (x - 3)/4 = (x + 3)/7. Cross multiply to get 7(x - 3) = 4(x + 3). Expand and solve for x to get 7x - 21 = 4x + 12. Simplify to get 3x = 33, and then divide by 3 to find x = 11. So, x equals 11.
"x" would equal 1 because 7/1 is 7 minus 2 equals 5 and 3/1 is 3 plus or + 2 is 5.
x/35 = 3/7 => x = 3/7 *35 = 3 * (35/7) = 3*5 = 15
1 x 3 x 3 x 7 x 7
You can produce an infinite number of ratios that are equal 3:7. You can do this by simply multiplying both 3 and 7 by the same number, so for example: 3 x 2:7 x 2 6:14 = 3:7 3 x 5:7 x 5 15:35 = 3:7