Mean = Average (14 + 6 + 4 + 12)/4 = ? (36)/4 = 9 Mean of the data is 9.
Mean(52349, 4) = (52349+ + 4)/2 = 26176.5
There is not much point in calculating the mean or mode of a single number. The mean of 5 is 5. The mode of 4 is 4.
The mean is the average = (6+9+101+4)/4 = 30
4^4 = 4*4*4*4 = 256
The balanced equation for the reaction between copper sulfate solution (CuSO4) and ammonia solution (NH3) is: CuSO4 + 4NH3 -> [Cu(NH3)4]SO4
The balanced equation for the reaction N2H4 → NH3 + N2 is: 3N2H4 → 4NH3 + N2
this is the balanced equation 4NH3 + 5O2 = 4NO + 6H2O
The balanced equation for the reaction of ammonia (NH3) with oxygen (O2) to form nitrogen monoxide (NO) and water (H2O) is: 4NH3 + 5O2 → 4NO + 6H2O
Yes - there are equal values of nitrogen (4) and hydrogen (12) on both sides of this equation, and all molecular formulas are in empirical form.
Tetraamminechloridocobalt(III) chloride
The balanced equation for the reaction between copper sulfate (CuSO4) and ammonia (NH3) is CuSO4 + 4NH3 → Cu(NH3)4SO4.
nitrogen monoxide and Water The balanced equation is as follow: 4NH3 + 5O2-->4NO + 6H2O
4NH3(g) + 5O2(g) 4NO(g) + 6H2O(g)
You can use the balanced chemical equation to determine the number of moles of nitric oxide formed. The balanced equation is 4NH3 + 5O2 → 4NO + 6H2O, indicating a 1:1 mole ratio between NH3 and NO. As only NH3 is limiting in this case, 3.80 moles of NH3 will produce 3.80 moles of NO.
The balanced equation for NH3 being burned in oxygen to form water and nitrogen dioxide is: 4NH3 + 5O2 → 4H2O + 6NO2
When ammonia is added to copper sulfate, a blue precipitate of copper hydroxide forms, as they react to produce a complex ion. The reaction can be represented by the equation: CuSO4 + 4NH3 -> [Cu(NH3)4]SO4.