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Mean = Average (14 + 6 + 4 + 12)/4 = ? (36)/4 = 9 Mean of the data is 9.
Mean(52349, 4) = (52349+ + 4)/2 = 26176.5
There is not much point in calculating the mean or mode of a single number. The mean of 5 is 5. The mode of 4 is 4.
The mean is the average = (6+9+101+4)/4 = 30
4^4 = 4*4*4*4 = 256
The balanced equation for the reaction between copper sulfate solution (CuSO4) and ammonia solution (NH3) is: CuSO4 + 4NH3 -> [Cu(NH3)4]SO4
The balanced equation for the reaction N2H4 → NH3 + N2 is: 3N2H4 → 4NH3 + N2
Tetraamminechloridocobalt(III) chloride
The balanced equation for the reaction of ammonia (NH3) with oxygen (O2) to form nitrogen monoxide (NO) and water (H2O) is: 4NH3 + 5O2 → 4NO + 6H2O
Yes - there are equal values of nitrogen (4) and hydrogen (12) on both sides of this equation, and all molecular formulas are in empirical form.
this is the balanced equation 4NH3 + 5O2 = 4NO + 6H2O
The balanced chemical equation for the reaction between ammonia (NH3) and oxygen gas (O2) is 4 NH3 + 5 O2 → 4 NO + 6 H2O. This means that 5 moles of O2 are needed to react with 4 moles of NH3. With 10.0 moles of NH3, you would need 12.5 moles of O2 (10.0 moles NH3 x 5 moles O2 / 4 moles NH3).
The balanced equation for the reaction between copper sulfate (CuSO4) and ammonia (NH3) is CuSO4 + 4NH3 → Cu(NH3)4SO4.
nitrogen monoxide and Water The balanced equation is as follow: 4NH3 + 5O2-->4NO + 6H2O
4NH3(g) + 5O2(g) 4NO(g) + 6H2O(g)
You can use the balanced chemical equation to determine the number of moles of nitric oxide formed. The balanced equation is 4NH3 + 5O2 → 4NO + 6H2O, indicating a 1:1 mole ratio between NH3 and NO. As only NH3 is limiting in this case, 3.80 moles of NH3 will produce 3.80 moles of NO.
4nh3 + 5o2 --> 4no + 6h2o