5x^3 + 15 x^2 - 125x - 375 = 5(x^3 + 3 x^2 - 25x - 75) = 5[(x^3 + 3 x^2) - (25x + 75)] = 5[x^2(x + 3) - 25(x + 3)] = 5[(x + 3)(x^2 - 25)] = 5(x + 3)(x + 5)(x -5)
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It is a bit difficult to be sure because I cannot see superscripts for the powers of x. x^4 + 3*x^3 + 125*x + 375 = x^3*(x+3) + 125*(x+3) =(x^3 + 125)*(x+3) And then using x^3+y^3 = (x+y)*(x^2-x*y+y^2) with y = 5 =(x+5)*(X^2-x+25)*(x+3)
(375) + (20%) = 375.2450 is 20% more than 375 .
325 + 50 = 375
Divide by 1, 3, 5 and 15.1, 3, 5, 15, 25, 75, 125, 375
300 + (25%) = 375