x-n = 1 / xn
The geometric mean of 'A' and 'B' is the square root of ( A x B ). Edit: The geometric mean of n positive numbers, x1, x2, ... , xn is the nth root of x1*x2* ... *xn.
xn+1 = 1/2 ( xn + N/xn )
This is represented as the algebraic expression xn/n or xn ÷ n.
Suppose you have n observations {x1, x2, ... , xn} for a variable, X. Calculate m = (x1 + x2 + , ... , + xn)/n, the mean value. Calculate s2 = (x12 + x22 + , ... , + xn2)/n Then Variance = s2 - m2 = [mean of the squares] - [square of the mean] and the standard deviation = sqrt(Variance)
In mathematics, XN typically represents a variable (X) raised to a power (N). This is known as exponentiation, where X is the base and N is the exponent. The expression XN is equal to multiplying X by itself N times. For example, X2 means X squared, which is X multiplied by itself two times.
x-n = 1 / xn
It means the relation between the variables, x1, x2, x3, ..., xn is of the form a1*x1 + a2*x2 + a3*x3 + ... +an*xn = b, where a1, a2, a3, ...,an and b are constants.
If by "xn" you mean ax^n then the answer is "a"
The geometric mean of 'A' and 'B' is the square root of ( A x B ). Edit: The geometric mean of n positive numbers, x1, x2, ... , xn is the nth root of x1*x2* ... *xn.
(xn+2-1)/(x2-1)ExplanationLet Y=1+x2+x4+...+xn. Now notice that:Y=1+x2+x4+...+xn=x2(1+x2+x4+...+xn-2)+1Y+xn+2=x2(1+x2+x4+...+xn-2+xn)+1Y+xn+2=x2*Y+1Y+xn+2-x2*Y=1Y-x2*Y=1-xn+2Y(1-x2)=1-xn+2Y=(1-xn+2)/(1-x2)=(xn+2-1)/(x2-1)
xn+1 = 1/2 ( xn + N/xn )
xn- yn=(x - y)(xn-1 + xn-2y +xn-3y2 +. . .+x2yn-3+xyn-2 + yn-1)
Y=Xn Y/n=X
This is represented as the algebraic expression xn/n or xn ÷ n.
Yes you (usually) can, though it may depend on your particular C implementation. // A complete (if useless) C program to compute the square root of 2 and then exit. // No headers required. double sqroot(const double s) { double xn = s / 2.0; double lastX = 0.0; while(xn != lastX) { lastX = xn; xn = (xn + s/xn) / 2.0; } return xn; } int main() { double sqrt2 = sqrt(2); return 0; }
Suppose you have n observations {x1, x2, ... , xn} for a variable, X. Calculate m = (x1 + x2 + , ... , + xn)/n, the mean value. Calculate s2 = (x12 + x22 + , ... , + xn2)/n Then Variance = s2 - m2 = [mean of the squares] - [square of the mean] and the standard deviation = sqrt(Variance)