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How do you factor a5 plus b5 equals?
a5+b5 = (a+b) (a4-a3b+a2b2-ab3+b4)
What is (ab3)4?
Assuming that you want (ab^3)^4, which is impossible to ask given the crap browser used by Answers, the solution is A^4b^12.
Prove that the line which divides the nonparallel sides of a trapezium proportionally is parallel to the third side.?
Theorem 3 : Any line parallel to the sides of a trapezium (trapezoid) divides the non-parallel sides proportionally.Given : ABCD is a trapezoid. DC AB. EF AB and EF DC.Prove that : AE/ED = BF/FCConstruction : Join AC, meeting EF in G.StatementsReasons1) EG DC1) Given (in ΔADC)2) AE/ED = AG/GC2) By Basic proportionality theorem3) GF AB3) Given (in ΔABC)4) AG/GC = BF/FC4)By Basic proportionality theorem5) AE/ED = BF/FC5) From (2) and (4)Source: ask-math.com
What is the density of AB3 rock?
The density of a rock labeled as AB3 can vary depending on the specific composition of the rock. Generally, rock densities fall within the range of 2 to 3 g/cm^3. However, without more specific information about the composition of the AB3 rock, an exact density cannot be determined.
What is the GCF of a2b3 and ab3?
The GCF is ab3
What molecular geometries are associated with AB3?
The molecular geometry associated with AB3 is trigonal planar. This geometry results when there are three bonding pairs and no lone pairs around the central atom. Additionally, all bond angles in a molecule with AB3 geometry are 120 degrees.
What shape is possible for the formula ab3 according to vsepr theory?
The formula ab3 corresponds to a trigonal planar shape in VSEPR theory. This means that the central atom is surrounded by three bonded atoms and has a bond angle of 120 degrees between them.
A and b are prime numbers ab3 equals 54 find the values of a and b?
54 = 2 x 3 x 3 x 3 = 2 x 33. Thus if ab3 = 54 and a, b are prime, then a=2, b=3.
What geometries will give nonpolar molecules for AB3?
For an AB3 molecule to be nonpolar, the central atom (A) must have the same atoms bonded to it (all atoms must be identical, like in BF3). This results in a symmetrical distribution of charge and no net dipole moment, making the molecule nonpolar.
How do you factor a5 plus b5 equals?
a5+b5 = (a+b) (a4-a3b+a2b2-ab3+b4)
What is (ab3)4?
Assuming that you want (ab^3)^4, which is impossible to ask given the crap browser used by Answers, the solution is A^4b^12.
Why don't all molecules with the general atomic formula AB3 have the same shape?
Not all molecules with the general atomic formula AB₃ have the same shape because the shape of a molecule is determined by the arrangement of atoms around the central atom. Factors such as bond angles, lone pairs of electrons, and steric hindrance can influence the shape of the molecule. Therefore, even with the same formula, different molecules can have different shapes based on these factors.
What is the qoutient when 32a 2 b 12 ab3 c is divided by 8 ab?
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "equals", "squared", "cubed" etc. Please use "brackets" (or parentheses) because it is impossible to work out whether x plus y squared is x + y^2 of (x + y)^2.
What are the piano notes for Halloween theme?
Right Hand:1:C#, F#, F#, C#, F#, F#, C#, F#, D, F#2: C, F, F, C, F, F, C, F, C#, F3: B, E, E, B, E, E, B, E, C, E4: Bb, Eb, Eb, Bb, Eb, Eb, Bb, Eb, B, Eb5: F#, B, B, F#, B, B, F#, B, G, BLeft Hand1: F#, A, Bb, F#, A, Bb2: E, G, Ab, E, G, Ab3: B, D, E, F#, B, D, E, F#
Is AlN polar or non polar?
One can determine the polarity of AlBr3 by first drawing a simple Lewis structure. We know that Aluminum has three (3) valence electrons and Bromine has seven (7) valence electrons. To figure out the total number of valence electrons in the molecule before drawing the structure we do the following: V = 3 + (7 x 3) V = 24 electrons in AlBr3 Now we can draw a simple Lewis structure: Br - Al - Br l Br Each Bromine has one single bond with Aluminum and 3 lone pairs of electrons. If we calculate that each bond is two electrons and each Bromine has 6 electrons (3 lone pairs) then: 6 + 6 + 6 (from the Bromine atoms) + 2 + 2 + 2 (from the three bonds) = 24 electrons So, we know that our structure is correct. Now we check the VSEPR type. The letter 'A' represents the central atom (in our case, Aluminum), the letter 'B' represents the number of bonding atoms to the central element (Bromine) and the letter 'E' represents the number of lone electron pairs on the CENTRAL atom (Aluminum). From this we can tell that our VSEPR configuration is AB3 (no 'E' value as there are no lone pairs of electrons on Aluminum). Finally, we match our VSEPR configuration, AB3, with what VSEPR says about polarity. Because our molecule consists of a central atom surrounded by three bonding elements that are the same, our molecule is NON-POLAR. *Note: If the molecule has a central atom surrounded by three bonding elements that are not the same, as in the case of COCl2, the molecule is polar.
