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Why cant n(AUB) equal to n(a) plus n(b) in math?
I assume that with n(...) you mean the size of the set. It sure can; but it need not be.
How do you expand binomials A plus b to the degree of n?
It isnC0*A^n*b^0 + nC1*A^(n-1)*b^1 + ... + nCr*A^(n-r)*b^r + ... + nCn*A^0*b^n where nCr = n!/[r!*(n-r)!]
How do you find the power of a quotient?
The power of a quotient is the quotient of the power! (a/b)^n = (a^n) / (b^n) where a/b is the quotient and n is the power.
What is the formula for geometric mean?
The geometric mean of 'A' and 'B' is the square root of ( A x B ). Edit: The geometric mean of n positive numbers, x1, x2, ... , xn is the nth root of x1*x2* ... *xn.
What is the recursive formula for A B C?
The recursive formula for a sequence typically defines each term based on previous terms. For a sequence denoted as ( A(n) ), ( B(n) ), and ( C(n) ), a common recursive approach might be: ( A(n) = A(n-1) + B(n-1) ) ( B(n) = B(n-1) + C(n-1) ) ( C(n) = C(n-1) + A(n-1) ) These formulas assume initial values are provided for ( A(0) ), ( B(0) ), and ( C(0) ). Adjustments can be made based on the specific context or properties of the sequence.
What if you have the mean and then 2 more numbers how do you find the new mean?
You can only answer this question if you know how many numbers there were before. (If you know how many were there after, then subtracting two gives you the number before). So suppose there were n numbers with mean x. And you add two more numbers, a and b. That means the sum of the n numbers was n*x. Sum of the n+2 numbers is n*x + a + b So the new mean is (n*x + a + b)/(n + 2)
Why cant n(AUB) equal to n(a) plus n(b) in math?
I assume that with n(...) you mean the size of the set. It sure can; but it need not be.
How do you expand binomials A plus b to the degree of n?
It isnC0*A^n*b^0 + nC1*A^(n-1)*b^1 + ... + nCr*A^(n-r)*b^r + ... + nCn*A^0*b^n where nCr = n!/[r!*(n-r)!]
What song says b bananas b a n n a s?
Its spelt B-A-N-A-N-A-S its by Gwen Stephani
How do you find the power of a quotient?
The power of a quotient is the quotient of the power! (a/b)^n = (a^n) / (b^n) where a/b is the quotient and n is the power.
How much is 1 share of NASDAQ worth curently?
its worth nothing n stuff (b^o^)b its worth nothing n stuff (b^o^)b its worth nothing n stuff (b^o^)b its worth nothing n stuff (b^o^)b its worth nothing n stuff (b^o^)b its worth nothing n stuff (b^o^)b
What is adding subtracting multiplying or dividing each side of an equality by the same number?
In algebra this is a method of solving equations for a variable. It stands to reason that if A=B then A+1=B+1. In fact it is true that if N is a number then A+N=B+N A-N=B-N A x N = B x N A/N = B/N We can do anything we want as long as we do the same thing to both sides.
What is the formula for geometric mean?
The geometric mean of 'A' and 'B' is the square root of ( A x B ). Edit: The geometric mean of n positive numbers, x1, x2, ... , xn is the nth root of x1*x2* ... *xn.
If a divides b which one is the denomitor?
If a divides b then a is a factor of b and b is a multiple of a.Either of them could be the denominator. In a/b, b is the denominator while in b/a, a is the denominator.------------------------------------------------------------------------------------------------------------------If a divides b then b=n*a for some number n. Thus n=b/a
What is 5 n is b n please?
b is equal to 5
What is memory variable. how can you create array memory variable?
You probably mean pointer variable rather than memory variable. You create an array of pointer variables just as you would an array of any other type: #include<stdio.h> #include<malloc.h> // Fixed-length arrays: void foo1 (void) { const unsigned n = 10; unsigned i; // an array of n int types int a[n]; // an array of n pointer-to-int types int* b[n]; // assign the address of each indexed element in a[] to the corresponding pointer element in b[] for (i=0; i<n; ++i) b[i] = &a[i]; // assign values to integers in a[] via pointers in b[] for (i=0; i<n; ++i) *b[i] = i * 10; // print the values in a[] printf ("a[] = {"); for (i=0; i<n; ++i) printf("%d%s", a[i], i<n-1?", ":""); printf ("}\n"); // print the values pointed to by b[] printf ("b[] = {"); for (i=0; i<n; ++i) printf("%d%s", *b[i], i<n-1?", ":""); printf ("}\n"); } // Variable-length arrays: void foo2 (unsigned n) { unsigned i; // an array of n int types int* a = (int*) malloc (n * sizeof (int)); // an array of n pointer-to-int types int** b = (int**) malloc (n * sizeof (int*)); // assign the address of each indexed element in a[] to the corresponding pointer element in b[] for (i=0; i<n; ++i) b[i] = &a[i]; // assign values to integers in a[] via pointers in b[] for (i=0; i<n; ++i) *b[i] = i * 10; // print the values in a[] printf ("a[] = {"); for (i=0; i<n; ++i) printf("%d%s", a[i], i<n-1?", ":""); printf ("}\n"); // print the values pointed to by b[] printf ("b[] = {"); for (i=0; i<n; ++i) printf("%d%s", *b[i], i<n-1?", ":""); printf ("}\n"); // release allocated resources free (b); free (a); } int main () { foo1 (); foo2 (10); return 0; }
How many links will a network with n node sand b branches have?
The number of links are: L=b-(n-1)=b-n+1 Where b=Number of branches n=number of nodes
