Both 14 and 8 can go into their least common multiple (LCM), which is 56. This means 56 is the smallest number that is divisible by both 14 and 8. Additionally, any multiple of 56 will also be divisible by both numbers.
8 will go into 14 once with a remainder of 6 (or 1 3/4 times)
First, to simplify and show you a easy way to do negative variable problems, multiply both sides, all terms, by a negative 1. -1(-X + 8 = 14) X - 8 = -14 add the 8 to both sides X = -6 check in original equation -(-6) + 8 = 14 that negative times a negative makes the 6 positive 6 + 8 = 14 14 + 14 checks
Three times with eight remaining 14 + 14 + 14 + 8 = 50
14 = 2*7 49 = 7*7 So 1, -1, 7, -7 all go into both 14 and 49.
As 8 is even, and 3 is odd, I think only 1 can go into both.
14 and 28 can both go into any multiple of 28 .
Assume that the expression is: x + 14 = 8 Then subtract both sides by 14 to get: x + 14 - 14 = 8 - 14 x = -6 If x = 14 + 8, then x = 22.
114 ÷ 8 = 14 2/8 = 14¼ = 14.25
They both go into 1440, for example.
8 will go into 14 once with a remainder of 6 (or 1 3/4 times)
1 2 4 7 14 28
The greatest common factor of 8 and 14 is 2 To find the GCF of 8 and 14, list the factors for each one. The GCF is the highest factor they share. 8: 1, 2, 4, 8 14: 1, 2, 7, 14 The GCF of 8 and 14 is 2.
If: 3x+8 = 14 Then: 3x = 14-8 So: 3x = 6 Divide both sides by 3: x = 2
First, to simplify and show you a easy way to do negative variable problems, multiply both sides, all terms, by a negative 1. -1(-X + 8 = 14) X - 8 = -14 add the 8 to both sides X = -6 check in original equation -(-6) + 8 = 14 that negative times a negative makes the 6 positive 6 + 8 = 14 14 + 14 checks
Three times with eight remaining 14 + 14 + 14 + 8 = 50
No. 104 is not evenly divisible by 14.
14 = 2*7 49 = 7*7 So 1, -1, 7, -7 all go into both 14 and 49.