Any multiple of 40.
Both 20 and 8 go into 40, as it is the least common multiple (LCM) of the two numbers. Additionally, they both go into any multiple of 40, such as 80 or 120. Both numbers can also be used as factors in various equations or scenarios involving multiples.
The factors of 8 are: 1, 2, 4, and 8.The factors of 20 are: 1, 2, 4, 5, 10, and 20.The factors common to 8 and 20 are: 1, 2, and 4.Each of these guzinta both 8 and 20.
Both 15 and 20 can go into 60, as they are both factors of that number.
12
6x + 8 = 20 Subtract 8 from both sides: 6x = 12 Divide both sides by 6: x = 2
The factors of 8 are: 1, 2, 4, and 8.The factors of 20 are: 1, 2, 4, 5, 10, and 20.The factors common to 8 and 20 are: 1, 2, and 4.Each of these guzinta both 8 and 20.
Both 15 and 20 can go into 60, as they are both factors of that number.
The LCM of 8 & 20 is... 40
12
They both go into 1440, for example.
80/x = 8/20 Taking reciprocals of both sides, x/80 = 20/8 Multipling both sides by 80, x = 80*20/8 simplifying: x = 20*80/8 = 20*10 = 200.
6x + 8 = 20 Subtract 8 from both sides: 6x = 12 Divide both sides by 6: x = 2
40% x * 20 = 8 divide both sides by 20 end up with .4 as your answer. multiply * 100 = 40 %
First of all you need to line them up. 8/20 - 2/5 Next you need to find a common denominator. 20 is a common denominator between the 2. Then you change both denominators to the common one. 8/20=8/20, 2/5 x 4/4= 8/20 {Since 5x4=20, you have to do that on both sides to get the common denominator.} Then you subtract 8/20 - 8/20 = 0. So the answer is 0
As 8 is even, and 3 is odd, I think only 1 can go into both.
9x + 8 = 6x + 20(- 8 from both sides)9x = 6x + 12(- 6x from both sides)3x = 12(divide both sides by 3)x = 4
No, but these numbers do go into 20 evenly: 1, 2, 4, 5, 10, 20.