R and > with a line under it (i can't do it on this website) and then C or R is greater than or equal to C
32 F is equal to 0 C. 212 F is equal to 100 C. and at -40, F and C are the same.
No.Neither are commutative: a - b does not equal b - a, and a/b does not equal b/a.Neither is associative: (a - b) - c does not equal a - (b - c), and (a/b)/c does not equal a/(b/c).Examples of these are:4 - 2 does not equal 2 - 4.1/3 does not equal 3/1.(6 - 5) - 1 does not equal 6 - (5 - 1).(10/2)/2 does not equal 10/(2/2).
The Roman numeral C is equal to 100. It is the next one after L, 50.
Yes, because a^2 + b^2 = c^2, where a and b are legs and c is the hypotenuse. Therefore, if a and b are equal, so will c.
You can use if-else statements to check for equality.Eg:char a, b, c;scanf("%c%c%c", &a, &b, &c);if( a==b && b==c)printf("They are equal\n");elseprintf("They are not equal\n");
c is less than or equal to 29
30 c
What is "c".
if b+c/a = c+a/b = a+b/c and a+b+c not equal to 0 then show that each of these ratio is equal to 2
R and > with a line under it (i can't do it on this website) and then C or R is greater than or equal to C
32 F is equal to 0 C. 212 F is equal to 100 C. and at -40, F and C are the same.
No.Neither are commutative: a - b does not equal b - a, and a/b does not equal b/a.Neither is associative: (a - b) - c does not equal a - (b - c), and (a/b)/c does not equal a/(b/c).Examples of these are:4 - 2 does not equal 2 - 4.1/3 does not equal 3/1.(6 - 5) - 1 does not equal 6 - (5 - 1).(10/2)/2 does not equal 10/(2/2).
The Roman numeral C is equal to 100. It is the next one after L, 50.
Yes, because a^2 + b^2 = c^2, where a and b are legs and c is the hypotenuse. Therefore, if a and b are equal, so will c.
30 c
c + c + 2c + c + c = 6c