The variable c times the variable b simply equals cb. Just as the variable x times the variable y would equal xy, and so on.
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b divided by 2
Associative: (a + b) + c = a + (b + c) (a x b) x c = a x (b x c)
suppose x is in B. there are two cases you have to consider. 1. x is in A. 2. x is not in A Case 1: x is in A. x is also in B. then x is in A intersection B. Since A intersection B = A intersection C, then this means x is in A intersection C. this implies that x is in C. Case 2: x is not in A. then x is in B. We know that x is in A union B. Since A union B = A union C, this means that x is in A or x is in C. since x is not in A, it follows that x is in C. We have shown that B is a subset of C. To show that C is subset of B, we do the same as above.
(a x b) x c = a x (b x c)
For any three numbers a, b, and c:a + b = b + a (commutative law)(a + b) + c = a + (b + c) (associative law)Both the commutative and associative laws are also valid for multiplication.a x (b + c) = (a x b) + (a x c) (distributive law)For any three numbers a, b, and c:a + b = b + a (commutative law)(a + b) + c = a + (b + c) (associative law)Both the commutative and associative laws are also valid for multiplication.a x (b + c) = (a x b) + (a x c) (distributive law)For any three numbers a, b, and c:a + b = b + a (commutative law)(a + b) + c = a + (b + c) (associative law)Both the commutative and associative laws are also valid for multiplication.a x (b + c) = (a x b) + (a x c) (distributive law)For any three numbers a, b, and c:a + b = b + a (commutative law)(a + b) + c = a + (b + c) (associative law)Both the commutative and associative laws are also valid for multiplication.a x (b + c) = (a x b) + (a x c) (distributive law)