The numbers are perfect cubes, so d will also be a perfect cube.
125 (the sequence is successive numbers cubed)
64
The sequence consists of the cubes of consecutive integers: (1^3 = 1), (2^3 = 8), (3^3 = 27), (4^3 = 64), (5^3 = 125), and (6^3 = 216). Therefore, the missing number in the sequence is 64.
125 13 23 43 53...
To find the number of odd numbers between 1 and 125, we note that the odd numbers in this range form an arithmetic sequence starting at 1 and ending at 125, with a common difference of 2. The sequence can be expressed as 1, 3, 5, ..., 125. The number of terms in this sequence can be calculated using the formula for the nth term of an arithmetic sequence: ( n = \frac{(last - first)}{difference} + 1 ). Substituting the values, we get ( n = \frac{(125 - 1)}{2} + 1 = 63 ). Thus, there are 63 odd numbers between 1 and 125.
125 is equal to 125.No other number is equal to 125.
These are perfect cubes (of 1, 2 and 3) so the next two are 64 and 125
13 ...23 ...33 ...43 ...53=125■
125 (the sequence is successive numbers cubed)
125 - x.
64
64 should be in between 27 and 125.
1 x 125, 5 x 25
the next number in the sequence 1 5 25 125 is 625
125 the number cuts in half everytime
343.
125 13 23 43 53...