Well, let's see:Force of gravity = G M1 M2 / R2So G = (force) x (distance)2 / (mass)2 = (M L / T2) x (L2) / (M2) = (M L3) / (M2 T2) =(Length)3 (Mass)-1(Time)-2
You have to divide by a trillion. So x g/m2 is 0.000000000001x g/um2
Assuming you mean 12 Square Meters (m2)12 m2 x 10.76391 = Answer 129.16692 Sq Ft
Law of Gravity: Fg = G(m1*m2)/r^2
Square Metre ...... eg 3m2 = 3 square metres
The unit "g over m2" is not an SI unit for density. SI unit for density is kg/m3 or g/cm3 or g/mL, which all represent mass per unit volume. The unit "g over m2" represents mass per unit area, not mass per unit volume.
The force, written as an equation, is:F = G (m1)(m2) / r2, whereF is the Force between the massesG is the gravitational constant (~= 6.674 x 10-11 N m2/kg2)m1 is one of the massesm2 is the other massr is the distance between the masses (center to center)Take the formula, and solve for r (I'll show the steps): Fold = G (m1)(m2) / r2.(r2)(Fold)= G (m1)(m2)(r2)= G (m1)(m2) / (Fold)r= √ [ G (m1)(m2) / (Fold) ]Plug the formula into itself, but remember, r = 3r (it tripled).Fnew= G (m1)(m2) / (3r)2.Fnew= G (m1)(m2) /(3√ [ G (m1)(m2) / (Fold) ])2.Fnew=G (m1)(m2)/(32G (m1)(m2) / (Fold) )
85 g / m2
the unit is : g/m2
The equation for calculating it would be g = G (m1) (m2) / (radius or distance ^2) where g = gravitational attraction, G is constant of universal gravitation, and m1 and m2 are the masses of the two objects
What is?? F = G m1 m2 / d2
What is?? F = G m1 m2 / d2
The force between two massess m1 and m2 is given by F = G m1 m2 / r^2 G is gravitational constant. r is the distance between the masses.
g minor harmonic given had an error D major 5 first inversion G minor i D major 5 given M3 p4 M2 M2 m3 p8 Half Cadence Your welcome. (=
weight, w = G * m1 * m2 / r^2, where G = the universal gravitational constant, m1 = the mass of the object, m2 = the mass of the earth, and r = the separation between the center of gravity of the object and that of the earth. w1 = G * m1 * m2 /(r1^2) -- > the weight when r = r1 w2 = G * m1 * m2 /(r2^2) -- > the weight when r = r2 Given: r2 = 4 * r1 w2 = G * m1 * m2 /(16 r1^2) = w1 / 16 Hence, the object will be 16 times lighter when it is situated 4 times farther away.
G=m1*m2/d^2
25kg = 25000 g1ha = 10000 m2 25000 g / 10000 m2 gives 40m2 for 100g